Formatting input (removing leading zeros and decimal places) in C90?

#include <stdio.h>

int intVal(int x)
{
    if(x < '0' || x > '9'){
        return 0;
    }
    else{
        x = x - '0';
        return x;
    }
}

int main(void)
{
    int c, num, prev;

    while((c = getchar()) != EOF){
        num = (intVal(prev) * 10) + intVal(c);
        prev = num;
        printf("%d", num);
    }
    return开发者_如何学编程 0;
}

What I want to do with this program is input an arbitrary number to be read a char at a time, then format it into an int so that I can work with it (Don't want to use printf formatting) Also, I am only allowed to use getchar and printf for this assignment.

Sample Input: 0001234.5

edit Desired Output: <1234>(5) Actual Output: 0001234050

I feel like I'm on the cusp of an epiphany but I've hit a roadblock, please help?

*edit I forgot to mention that the END result I am going for is to have the non-decimal numbers enclosed in <1234> and the decimal numbers in brackets (5)

A few things:

• For a start, you're calling intVal() on prev, which is going to do all sorts of crazy things.
• You have no handling for '.'.
• An int cannot store values with fractional parts.
• You're printing out the entire number on every iteration.
• You aren't initializing prev to 0.

Try it (without sign evaluation and error handling):

int main(void)
{
    double x=0,op=0;
    int c;

    while((c = getchar()) != EOF && c!='\n')
      if( c=='.' )
        op++;
      else
      if( op )
        x += (op/=10) * intVal(c);
      else
        x = x*10 + intVal(c);

    printf("%f",x);
    return 0;
}

Your function intVal is total wrong according to your requirement.

If you want get <1234>(5) from 0001234.5, the easiest way is using scanf:

sscanf("%d.%d", &a, &b);
printf("<%d>(%d)\n", a, b);

see man scanf