PHP: Is there a function that converts a date string in a human readable format?

I want to convert a date string like "19.11.2009 14:00" into the age of i开发者_StackOverflowt now like "for 2 minutes" or "for 1 week" or "for 2 days"

Is there some code around?

$dateString = strtotime('19.11.2009 14.00');
$now = time();

$time = $dateString - $now;

if($time > 60 && $time < 3600) echo $time/60.' minutes remaining';
else if($time > 3600 && $time < 86400) echo $time/3600.' hours remaining';
else if($time > 86400 && $time < 604800) echo $time/86400.' days remaining';
else if($time > 604800 && $time < 18144000) echo $time/604800.' weeks remaining';
else if($time > 18144000 && $time < 217728000) echo $time/18144000.' months remaining';
else if($time > 217728000) echo $time/217728000.' years remaining';

Something like this

define('MINUTE',60);
define('HOUR',60*MINUTE);
define('DAY',24*HOUR);
define('WEEK',7*DAY);
define('MONTH',30*DAY);

$pastDate=strtotime($dateString);
$seconds=time()-$pastDate;
if ($seconds>MONTH)
  return $seconds/MONTH . " months";
if ($seconds>WEEK)
  return $seconds/WEEK . " weeks";
if ($seconds>DAY)
  return $seconds/DAY . " days";
if ($seconds>HOUR)
  return $seconds/HOUR . " hours";
if ($seconds>MINUTE)
  return $seconds/MINUTE . " minutes";
return $seconds . " seconds";

If you're in PHP 5.3 you could also use DateTime:diff.

$start = new DateTime('now');
$time_span = $start->diff(new DateTime($dateString));
var_dump($time_span);

This may not be 100% what you want obviously -- others have given you great answers -- but something like this may be a good alternative to a "human readable" date format.

I dug this up from some code I used quite a while ago. I haven't tested this in a while, but last I remember it worked great. I wanted to replicate something like what Facebook uses, like "5 seconds ago", but it also works for the future, using "in ..." instead of "... ago". You can probably modify this to get as much or as little detail as you want.

/**
 * Returns the amount of time that has passed from the current date
 * or the amount of time from the current date until the specified date
 *
 * Returns in the form of a partial sentence. Some examples:
 *
 * In 25 days
 * Tomorrow
 * Yesterday
 * 4 months ago
 * Next month
 * Last month
 * (etc)
 *
 * @param string $date
 * @return string
 */
public static function calculateHowLong($date) {
  // start by converting to unix time
  $when = date("U", strtotime($date));
  $isPast = ($when < time());

  $how_long = abs(time() - $when);
  if ($how_long < 60) {
    $return =  "{$how_long} seconds";
    if ($isPast) $return .= " ago"; else $return = "In {$return}";

  } elseif ($how_long < 60 * 60) {
    $return =  (int) ($how_long / 60) . " minutes";
    if ($isPast) $return .= " ago"; else $return = "In {$return}";

  } elseif ($how_long < 60 * 60 * 24) {
    $return =  (int) ($how_long / (60 * 60)) . " hours";
    if ($isPast) $return .= " ago"; else $return = "In {$return}";

  } elseif ($how_long < 60 * 60 * 24 * 2) {
    if ($isPast) $return = "Yesterday"; else $return = "Tomorrow";

  } elseif ($how_long < 60 * 60 * 24 * 7) {
    $return =  (int) ($how_long / (60 * 60 * 24)) . " days";
    if ($isPast) $return .= " ago"; else $return = "In {$return}";

  } elseif ($how_long < 60 * 60 * 24 * 13) {
    if ($isPast) $return = "Last week"; else $return = "Next week";

  } elseif ($how_long < 60 * 60 * 24 * 7 * 4) {
    $return =  (int) ($how_long / (60 * 60 * 24 * 7)) . " weeks";
    if ($isPast) $return .= " ago"; else $return = "In {$return}";

  } elseif ($how_long < 60 * 60 * 24 * 30 * 2) {
    if ($isPast) $return = "Last month"; else $return = "Next month";

  } elseif ($how_long < 60 * 60 * 24 * 30 * 12) {
    $return =  (int) ($how_long / (60 * 60 * 24 * 30)) . " months";
    if ($isPast) $return .= " ago"; else $return = "In {$return}";

  } else {
    if ($isPast) $return = "More than 1 year ago"; else $return = "In more than 1 year";
  }

  return $return;
}

It's probably a little sloppy, but feel free to make it better.

I see earlier answers offering long-winded, "Write Everything Twice" (WET) instead of "Don't Repeat Yourself" (DRY) code. Worse, they are not leveraging the modern might of PHP's DateTime class. All of the obscurity and verbosity of performing mathematical calculations on unix time can be avoided. @Sergi hints in the right direction, but neglects to offer a complete solution.

Because the scope of this question states that incoming dates will be in the past and they are to be compared to the current date/time, I'll offer the following snippet to provide generalized English expressions as described in the question.

To cover cases where a number of weeks is desired, a condition needs to be implemented because the DateTime diff object does not provide a property for w (weeks). This is the only part of the snippet that requires a mathematical calculation.

Code: (Demo)

$date = '10.11.2021 14:00';
$diff = (new DateTime($date))->diff(new DateTime());

$lookup = [
    'y' => 'year',
    'm' => 'month',
    'd' => 'day',
    'h' => 'hour',
    'i' => 'minute',
];

foreach ($lookup as $property => $word) {
    if ($diff->$property) {
        if ($property === 'd' && $diff->$property >= 7) {
            $diff->w = (int)($diff->$property / 7);
            $property = 'w';
            $word = 'week';
        }
        $output = "for {$diff->$property} $word" . ($diff->$property !== 1 ? 's' : '');
        break;
    }
}
echo $output ?? 'for mere seconds';

Output (as table using 03.12.2021 13:00 as static current datetime):