How to determine the size of a Full-Text Index on SQL Server 2008 R2?
I have a SQL 2008 R2 database with some tables on it having some of those开发者_C百科 tables a Full-Text Index defined. I'd like to know how to determine the size of the index of a specific table, in order to control and predict it's growth.
Is there a way of doing this?
The catalog view sys.fulltext_index_fragments
keeps track of the size of each fragment, regardless of catalog, so you can take the SUM
this way. This assumes the limitation of one full-text index per table is going to remain the case. The following query will get you the size of each full-text index in the database, again regardless of catalog, but you could use the WHERE
clause if you only care about a specific table.
SELECT
[table] = OBJECT_SCHEMA_NAME(table_id) + '.' + OBJECT_NAME(table_id),
size_in_KB = CONVERT(DECIMAL(12,2), SUM(data_size/1024.0))
FROM sys.fulltext_index_fragments
-- WHERE table_id = OBJECT_ID('dbo.specific_table_name')
GROUP BY table_id;
Also note that if the count of fragments is high you might consider a reorganize.
If you are after a specific Catalogue Use SSMS - Clik on [Database] and expand the objects - Click on [Storage] - Right Click on {Specific Catalogue} - Choose Propertie and click. IN General TAB.. You will find the Catalogue Size = 'nn'
I use something similar to this (which will also calculate the size of XML-indexes, ... if present)
SELECT S.name,
SO.name,
SIT.internal_type_desc,
rows = CASE WHEN GROUPING(SIT.internal_type_desc) = 0 THEN SUM(SP.rows)
END,
TotalSpaceGB = SUM(SAU.total_pages) * 8 / 1048576.0,
UsedSpaceGB = SUM(SAU.used_pages) * 8 / 1048576.0,
UnusedSpaceGB = SUM(SAU.total_pages - SAU.used_pages) * 8 / 1048576.0,
TotalSpaceKB = SUM(SAU.total_pages) * 8,
UsedSpaceKB = SUM(SAU.used_pages) * 8,
UnusedSpaceKB = SUM(SAU.total_pages - SAU.used_pages) * 8
FROM sys.objects SO
INNER JOIN sys.schemas S ON S.schema_id = SO.schema_id
INNER JOIN sys.internal_tables SIT ON SIT.parent_object_id = SO.object_id
INNER JOIN sys.partitions SP ON SP.object_id = SIT.object_id
INNER JOIN sys.allocation_units SAU ON (SAU.type IN (1, 3)
AND SAU.container_id = SP.hobt_id)
OR (SAU.type = 2
AND SAU.container_id = SP.partition_id)
WHERE S.name = 'schema'
--AND SO.name IN ('TableName')
GROUP BY GROUPING SETS(
(S.name,
SO.name,
SIT.internal_type_desc),
(S.name, SO.name), (S.name), ())
ORDER BY S.name,
SO.name,
SIT.internal_type_desc;
This will generally give numbers higher than sys.fulltext_index_fragments
, but when combined with the sys.partitions
of the table, it will add up to the numbers returned from EXEC sys.sp_spaceused @objname = N'schema.TableName';
.
Tested with SQL Server 2016, but documentation says it should be present since 2008.
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