Find rows that have the same value on a column in MySQL

In a [member] table, some rows have the same value for the email column.

login_id | email
---------|---------------------
john     | john123@hotmail.com
peter    | peter456@gmail.com
johnny   | john123@hotmail.com
...

Some people used a different login_id but t开发者_开发百科he same email address, no unique constraint was set on this column. Now I need to find these rows and see if they should be removed.

What SQL statement should I use to find these rows? (MySQL 5)

This query will give you a list of email addresses and how many times they're used, with the most used addresses first.

SELECT email,
       count(*) AS c
FROM TABLE
GROUP BY email
HAVING c > 1
ORDER BY c DESC

If you want the full rows:

select * from table where email in (
    select email from table
    group by email having count(*) > 1
)

select email from mytable group by email having count(*) >1

Here is query to find email's which are used for more then one login_id:

SELECT email
FROM table
GROUP BY email
HAVING count(*) > 1

You'll need second (of nested) query to get list of login_id by email.

First part of accepted answer does not work for MSSQL.
This worked for me:

select email, COUNT(*) as C from table 
group by email having COUNT(*) >1 order by C desc

use this if your email column contains empty values

 select * from table where email in (
    select email from table group by email having count(*) > 1 and email != ''
    )

Thanks guys :-) I used the below because I only cared about those two columns and not so much about the rest. Worked great

  select email, login_id from table
    group by email, login_id
    having COUNT(email) > 1

I know this is a very old question but this is more for someone else who might have the same problem and I think this is more accurate to what was wanted.

SELECT * FROM member WHERE email = (Select email From member Where login_id = john123@hotmail.com) 

This will return all records that have john123@hotmail.com as a login_id value.

Get the entire record as you want using the condition with inner select query.

SELECT *
FROM   member
WHERE  email IN (SELECT email
                 FROM   member
                 WHERE  login_id = abcd.user@hotmail.com) 

This works best

Screenshot

SELECT RollId, count(*) AS c 
    FROM `tblstudents` 
    GROUP BY RollId 
    HAVING c > 1 
    ORDER BY c DESC

Very late to this thread, but I had a similar situation and the following worked on MySQL. The following query will also return all the rows that match the condition of duplicate emails

SELECT * FROM TABLE WHERE EMAIL IN 
       (SELECT * FROM 
            (SELECT EMAIL FROM TABLE GROUP BY EMAIL HAVING COUNT(EMAIL) > 1) 
        AS X);