How to load php in between this ' ' in a php code?
I have a problem with my code!
My code-
<?php
$replace = 'ISO Burning Programs/Active@ ISO Burner 2.1.0.0/SPTDinst-v162-x86.exe';
$result = preg_replace_callback('/([^\/]*)(\/|$)/', function($matches){
static $count = 0;
$count++;
return !empty($matches[1]) ? '
<body onload="filetype_main(document.getElementById(\'file_type_'.$count.'\'));">
<ul style="margin: 0px 0px 0px -20px;" type="none"><li id="file_type_li_'.$count.'">
<form id="file_type_'.$count.'">
<img alt="" name="file_img" class="file_img" id="file_img"/>
<input name="file_type_ext" id="file_type_ext" name="file_type_ext" value="'.$matches[1].'" type="text" size="30"/>
<font><?php echo "Cool";?>
'
.$matches[1].
'
</font></form></li></body>
' : '';
}, $replace);
echo "";
echo "Main Folder";
echo $result;
echo "";
?>
Now i want that my php code-
<?php echo "Cool"; ?>
To be properly shown like - Cool in my html page! But its not happening like that it doesn't show anything and when i see my source code using CHROME it shows the code in italics! Please help me!开发者_Python百科
Thanks Advance!
Why don't you just replace <?php echo "cool" ?> with "cool"?
In this case you can just replace <?php echo "Cool";?> to Cool.
But if you want to show a PHP variable value, you can just concatenate, just as you did with $count, for instance.
Change:
<?php echo "Cool";?>
to just
Cool
remove php tags near the cool
<?php
$replace = 'ISO Burning Programs/Active@ ISO Burner 2.1.0.0/SPTDinst-v162-x86.exe';
$result = preg_replace_callback('/([^\/]*)(\/|$)/', function($matches){
static $count = 0;
$count++;
return !empty($matches[1]) ? '
<body onload="filetype_main(document.getElementById(\'file_type_'.$count.'\'));">
<ul style="margin: 0px 0px 0px -20px;" type="none"><li id="file_type_li_'.$count.'">
<form id="file_type_'.$count.'">
<img alt="" name="file_img" class="file_img" id="file_img"/>
<input name="file_type_ext" id="file_type_ext" name="file_type_ext" value="'.$matches[1].'" type="text" size="30"/>
<font>'."Cool".
.$matches[1].
'
</font></form></li></body>
' : '';
}, $replace);
echo "";
echo "Main Folder";
echo $result;
echo "";
?>
HTML documents follow certain structure. Among other specs, there must be one <body></body> block. Your HTML includes three of these blocks so it's invalid.
Learn to use this tool:
- http://validator.w3.org/#validate_by_input
Once your HTML triggers zero errors, it'll be easy to append Cool.
Update:
I misread your question. PHP code inside a PHP string will never run. Compare this:
<?php
$output = '<?php echo "Foo"?>';
?>
... with this:
<?php echo "Foo"?>
加载中,请稍侯......
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