get lowermost left corner of an iamge and write text there

I'm trying to get the lowermost left (x,y) coordinates of an image. I'm doing that to be able to write a text in different-sized picture, in the left lowermost corner. Below is the code. Could you please help?

<?php
$white = imagecolorallocate($image2, 255, 255, 255);
$grey = imagecolorallocate($image2, 128, 128, 128);
$black = imagecolorallocate($image2, 0, 0, 0);
$textsize = 30;
$size = imagettfbbox($textsize, 0, $font, $text);
$xsize = abs($size[0]) + abs($size[2]);
$ysize = abs($size[5]) + ab开发者_高级运维s($size[1]);
$image2size = getimagesize("image2.jpg");
$textleftpos = round(($image2size[0] - $xsize) / 2);
$texttoppos = round(($image2size[1] + $ysize) / 2);
imagettftext($image2, $textsize, 0, $textleftpos, $texttoppos, $white, $font, $text);
imagejpeg($image2, "image3.jpg");
?>

$indentfromedge = 5; // or whatever you want for an indent
$textleftpos = $indentfromedge;
$texttoppos = $image2size[1] - $ysize - $indentfromedge;

I think is what you're going for. Replace the two lines with $text*pos in them with the above code.

On the left edge means an x-coordinate of 0 On the bottom edge means an y-coordinate equal to the height of the image minus the height of the text

So, say your text size is 30px:

$size = imagesize($img);
$x = 0;
$y = $size[1] - 30;
// assuming you're using GD1
imagettftext($image, 30, 0, $x, $y, $color, $font, "sample text");