Problem with Array Search in PHP

I am not finding what might be the problem in my program.

I am having an array like this

$arr = array("1", "urgent", "4", "low", "15", "avg");

When i am searching this array using

$key = array_search("4", $arr);// Working

Its is giving me the index of that element;

But when i am searching for "1" it is not giving me any index.

$key = array_search("4", $arr); // Not w开发者_JS百科orking here - for searching "1"

What might be the problem.

Thank You

http://ideone.com/e1n3r Your code does work fine. It returns key == 0, which is the key, where "1" is stored.

To get the difference between 0 and false you should use === operator, or its contrary !==:

$arr = array("1", "urgent", "4", "low", "15", "avg");

$key1 = array_search("1", $arr); 
var_dump($key1 === false);  // false (value exists)
var_dump($key1 !== false);  // true (value exists)

$key21 = array_search("21", $arr); 
var_dump($key21 === false); // true  (value does not exist)
var_dump($key21 !== false); // false (value does not exist)

array_search return key value of array.

    $arr = array("1", "urgent", "4", "low", "15", "avg");
    $key = array_search("4", $arr); 
   // give output is 2 which is key value 
    $key = array_search("1", $arr);
   //give output is 0 which is key value

I think you are using $key in thewrong way. $key = 0 and now if you do boolean evaluation it will act as false. You should use something like if($key >= 0) or if(is_int($key))

Remember that 0 is evaluated to FALSE in php.

so..

if($index = array_search("1",$arr)) {
    //will actually evaluate to false
}

In case you are using it this way and think it's not working because the conditional isn't technically failing, the value is evaluated as FALSE.