php passing URL

I have this URL:

http://www.example.com/get_开发者_JAVA百科url.php?ID=100&Link=http://www.test.com/page.php?l=1&m=7

When I print $_GET['Link'], I see only http://www.test.com/page.php?l=1.

Where is &m=7?

If you want to pass an url as a GET parameter, you'll have to URL-encode it.

The problem is, the server sees & as ending the Link parameter. This means you're actually getting:

$_GET['ID'] = '100';
$_GET['Link'] = 'http://www.test.com/page.php?l=1';
$_GET['m'] = '7';

What you want to do is use urlencode. Example:

$link = 'http://sample.com/hello?a=5&b=6&d=7';
$address = 'http://site.com/do_stuff.php?link='.urlencode($link)

External references:

• urlencode in PHP

It's a separate value. If you pass it this way, the GET values are:

ID=100
Link=http://www.test.com/page.php?l=1
m=7

The & character separates values passed by GET.

In order to pass the entire thing, you need to encode it properly (see Sebastian's answer).

(see sebastian's answer).The server sees & as the ending parameter so u won't get the values after &.If u want to get the entire thing u need to encode the entire link using "function urlencode()" before passing the parameters