Help with SQL query - show today birthday on top of the table

I have a table in SQL Server 2008

I need to have the first results be people who's birthday is today, and the rest of the results sort by fname,lname

for example, i have this table:

fname|lname|Tdate
AA   |111  |03/08
BB   |222  |18/01
FF   |11   |20/01
CC   |333  |31/07
DD   |444  |10/04
EE   |22  开发者_运维百科 |20/01

today = 20/01/2011

and i need to see this:

fname|lname|Tdate
FF   |11   |20/01
EE   |22   |20/01
AA   |111  |03/08
BB   |222  |18/01
CC   |333  |31/07
DD   |444  |10/04

How to do it ?

thanks in advance

Something like this at the end of your query.

order by 
case when cast(tdate as date) = cast(getdate() as date) THEN 1
else 0 end desc, 
fname, lname

SELECT FNAME, LNAME, TDATE ,1 AS RANK FROM WHERE TDATE=GETDATE()

UNION

SELECT FNAME, LNAME, TDATE ,2 AS RANK FROM WHERE TDATE<>GETDATE()

ORDER BY
    SIGN(ABS(DATEDIFF(day, Tdate, GETDATE()))),
    Tdate