Calling base class property from object of derived class without marking it virtual

How to call x of class a from object of class b without marking x of class a as virtual. Is it possible

public class a { public int x { get; set; } }
public class b : a { public int x { get; set; } }

public class c {
    a _a = new a();
    b _b = new开发者_StackOverflow中文版 b();
    public c()
    {
        int y=_a.x;
        y=_b.x;
        _b.x = y;
    }
}

base.x() should work inside the b type (but that isn't what you have here).

In the "method hiding" scenario (what you have), it also largely depends on what a variable is typed as, so casting to a should work:

a tmp = _b;
tmp.x = ... // talks to a.x, not b.x

or more succinctly:

((a)_b).x = ... // talks to a.x, not b.x

Use typecast:

public class c
{
  a _a = new a();
  b _b = new b();

  void Test() {
    int y = _b.x; // This is "x" of "b"
    a _b_as_a = (a)_b;
    int z = _b_as_a.x; // This is "x" of "a" of "b"
  }
}

Besides typecasting (as above, although that won't work if you don't know its parent's type) you can't, so I would advise re-structuring one of those classes. You should probably make x virtual, or change the property x inside class b to something different, or call base.x inside b's x implementation.