Undefined offset with count()
I have an array $MyArray
which has some elements which are also array (lets call them subarrays). I want to know how many elements the subarray with the most elements has. The problem is, that I don't know if the index exists:
max(
@count($MyArray[$i*7]),
@count($MyArray[$i*7+1]),
@count($MyArray[$i*7+2]),
@count($MyArray[$i*7+3]),
@count($MyArray[$i*7+4]),
@count($MyArray[$i*7+5]),
@count($MyArray[$i*7+6])
);
Struckture of $MyArray
:
Array(
12 => array (
0 => array ( 0 => 0, 1 => 1, ),
1 => array ( 0 => 13, 1 => 1, ),
2 => array ( 0 => 15, 1 => 1, ),
3 => array ( 0 => 20, 1 => 1, ),
4 => array ( 0 => 69, 1 => 1, )
),
5 => array (
0 => array ( 0 => 55, 1 => 1, ),
1 => array ( 0 => 32, 1 => 1, ),
2 =&g开发者_StackOverflow社区t; array ( 0 => 12, 1 => 1, ),
3 => array ( 0 => 21, 1 => 5, )
),
....
)
Can this be done better (faster)?
edit: I know foreach
and I don't want to loop over every element in this array. I just want an interval of it. @
is used, because I don't know if $MyArray[$i*7 + x]
is Null
or an array
.
$i
is a element of [0, 1, 2, 3, 4] (sometimes also 5)
$biggest = 0;
foreach ($MyArray as $value) {
if ($biggest < count($value)) {
$biggest = count($value);
}
}
I see, you want the size of the biggest array in the array, correct?
Simple and old school approach:
<?php
$max = -1;
foreach($MyArray as $subarray)
{
$items = count($subarray);
if($items > $max)
$max = $items;
}
echo $max;
?>
This works best since you only want to know how many elements the subarray with the most elements has.
$max = 0;
foreach ($MyArray as $value) {
$max = max($max,count($value));
}
Try this:
$arr = array();
for ($j=0;$j<=6;$j++) {
if (isset($MyArray[$i*7+$j])) $arr[] = count($MyArray[$i*7+$j]);
}
$result = max($arr);
I don't know exactly what $i
refers to though...
// get the interesting part of the array
$chunk = array_intersect_key($input_array, array_flip(range($i*7, $i*7+6)));
// max(count)
$max = $chunk ? max(array_map('count', $chunk)) : 0;
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