On a batch file calling php using Start, how do you log output?

I've got a batch f开发者_开发百科ile that did:

php-cgi runfile.php >> log.txt
php-cgi runfile2.php >> log.txt

Which correctly ran the first and pushed out hte output into the log.txt then called runfile2 and pushed out into the log.txt

But then I changed it so it would start both scripts at the same time on separate processes so the 2nd script wouldn't have to wait; as:

start php-cgi runfile.php >> log.txt
start php-cgi runfile2.php >> log.txt

Which allows the scripts to correctly run (I think); but the log.txt shows no output.

Any ideas?

Thanks, Mike

This worked for me:

log.bat

start /B dir C:\ >> log1.txt
start /B dir C:\WINDOWS >> log2.txt

It works like a charm. I have a series of :

start C:/[path_to_php]/php -f C:/[path_to_scrip1].php > C:/[path_to_log1].txt    
start C:/[path_to_php]/php -f C:/[path_to_scrip2].php > C:/[path_to_log2].txt

and it only worked like:

start /B C:/[path_to_php]/php -f C:/[path_to_scrip1].php > C:/[path_to_log1].txt
start /B C:/[path_to_php]/php -f C:/[path_to_scrip2].php > C:/[path_to_log2].txt

So thanks jnpcl.