开发者

Fill List with values from a for loop in Scala

I'm pretty new to scala and I am not able to solve this (pretty) 开发者_C百科trivial problem.

I know I can instantiate a List with predefined values like this:

val myList = List(1,2)

I want to fill a List with all Integers from 1 to 100000 . My Goal is not to use a var for the List and use a loop to fill the list.

Is there any "functional" way of doing this?


Either of these will do the trick. (If you try them in the REPL, though, be advised that it's going to try to print all million hundred thousand entries, which is generally not going to work.)

List.range(1,100001)
(1 to 100000).toList


I am also very new to Scala, it's pretty awesome isn't it.

Rex has the absolutely correct answer, but as food for thought: if you want a list that is not evaluated up front (perhaps the computations involved in evaluating the items in the list is expensive, or you just want to make things lazy), you can use a Stream.

Stream.from(0,1).takeWhile(_<=100000)

This can be used in most situations where you'd use a List.

0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜