How calculate checksum using 8-bit addition of all bytes in the data structure
I need to calculate checksum from byte array. Its some serial port pac开发者_如何学运维ket. I have just this text:
Checksum is calculated using 8-bit addition of all bytes in the data structure. Overflows are not taken into account (1 byte).
How do 8-bit addition?
Need it in C#.
Straight addition? Well, you could iterate over all the bytes pretty easily:
public static byte ComputeAdditionChecksum(byte[] data)
{
byte sum = 0;
unchecked // Let overflow occur without exceptions
{
foreach (byte b in data)
{
sum += b;
}
}
return sum;
}
Alternatively, using LINQ:
public static byte ComputeAdditionChecksum(byte[] data)
{
long longSum = data.Sum(x => (long) x);
return unchecked ((byte) longSum);
}
I'm using long
to avoid overflowing on a long stream - I'm assuming it will be less than 255 bytes :) In practice you'd probably be fine using int
instead of long
.
LINQ Solution
public static byte CheckSum(byte[] array)
{
return array.Aggregate<byte, byte>(0, (current, b) => (byte) ((current + b) & 0xff));
}
In C#, read data into byte type array, and add all bytes to a seperate byte variable to get checksum result.
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