TSQL Query to fetch row details of a table having the maximum value for a column
I have two tables.
Table 1
Num
1
2
3
Table 2
Num Date Amount
1 12/31 30
1 12/30 31
1 12/29 20
2 12/31 100
2 12/30 90
3 12/31 12
4 11/1 1
Now my result should have
Num Date Amount
1 12/31 30
2 12/31 100
3 12/31 12
(for the 'Num' values in table 1, join with table2 where the date is the most recent)
I am t开发者_如何转开发rying to write a tsql query to achieve this.
Any help is appreciated. Thanks
If you want the most recent date for each table1 num individually:
with maxdates as (
select T1.num, max(T2.date) as date
from table2 T2
join table1 T1
on T2.num = t1.num
group by T1.num
)
select t2.num, t2.date, t2.amount
from table2 T2
join maxdates M
on T2.num = M.num
and T2.date = M.date
or if you want the most recent date for all matching records in the table:
with maxdate as (
select max(T2.date) as date
from table2 T2
join table1 T1
on T2.num = t1.num
)
select t2.num, t2.date, t2.amount
from table2 T2
join table1 T1
on T2.num = T1.num
join maxdate M
on T2.date = M.date
Try this query:
SELECT b.*
FROM Table1 a INNER JOIN
(
SELECT a.*,
ROW_NUMBER() OVER(PARTITION BY a.Num ORDER BY Date DESC) rnk
FROM Table2 a
) b
ON a.Num = b.Num
AND rnk = 1
Try this
select t2.* from table2 as t2 inner join table1 as t1 on t2.num=t2.num
inner join
(
Select t2.num,max(t2.amount) as amount from table2
group by t2.num
) as t3 on t2.amount=t3.amount
DECLARE @t1 TABLE(num INT)
DECLARE @t2 TABLE(num INT, [date] NVARCHAR(5), amount INT)
INSERT INTO @t1 (num) VALUES (1),(2),(3)
INSERT INTO @t2 (num,[date],amount) VALUES (1,'12/31',30)
INSERT INTO @t2 (num,[date],amount) VALUES (1,'12/30',31)
INSERT INTO @t2 (num,[date],amount) VALUES (1,'12/29',20)
INSERT INTO @t2 (num,[date],amount) VALUES (2,'12/31',100)
INSERT INTO @t2 (num,[date],amount) VALUES (2,'12/30',90)
INSERT INTO @t2 (num,[date],amount) VALUES (3,'12/31',12)
INSERT INTO @t2 (num,[date],amount) VALUES (4,'11/01',1)
SELECT t2.num,t2.[date],amount
FROM @t1 t1 JOIN @t2 t2 ON t1.num = t2.num
WHERE t2.[date] in (
SELECT MAX(t3.[date])
FROM @t2 t3
WHERE t3.num = t2.num
)
ORDER BY t2.num
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