serialport connection for unknown device
I've coin machine acceptor set and I wanna connect this machine using serialport. My main problem is, I did try almost every setting to connect that machine. The pin numbers are written on the cable as 3th and 7th. So I try
private void Form1_Load(object sender, EventArgs e)
{
// SerialPort paraPort d开发者_运维技巧efined at designer's generated code
paraport = new SerialPort("COM1", 9600, Parity.None, 8, StopBits.One);
//I wanna access to windows controls from the thread
System.Windows.Forms.Form.CheckForIllegalCrossThreadCalls = false;
}
private void button2_Click(object sender, EventArgs e)
{
//paraPort is the name of serialport class
paraPort.ReadBufferSize = 1024;
paraPort.WriteBufferSize = 1024;
paraPort.ReadTimeout = 1000;
paraPort.WriteTimeout = 1000;
paraPort.NewLine = "\n";
//Because 7th pin is for RTS which means request 2 send
paraPort.Handshake = Handshake.RequestToSend;
//Data Terminal Ready Enable
paraPort.DtrEnable = true;
paraPort.RtsEnable = true;
paraPort.Open();
//Then Thread check the procedure inside of try - catch block
try{
// Thread money defined at designer's generated code
money = new Thread(new ThreadStart(CheckTheMachineState));
money.Start();
}catch(Exception e){
MessageBox.Show("thread cannot be created"+e.Message);
}
}
private void CheckTheMachineState()
{
richTextBox1.AppendText("Thread is running\n");
//I wanna get the value of IOCTL_SERIAL_WAIT_ON_MASK
//But I still don't know how
}
}
The machine is working well. But when I use paraPort.ReadBufferSize property, it gives me 0 when the coin accept :S. When I use the paraPort.Read method it throws an timeout exception :\
So What can I do for this stuff ? I'm using portmon tools to catch the coin machine signal.
IOCTL_SERIAL_WAIT_ON_MASK value is changed as SUCESS when I put the coin. How can I catch this value ?
After several days of work, I have figured out how to connect a coin acceptor/validator machine to a PC via serial port using VB6, such that every coin inserted in the slot will trigger a signal that will be caught by the PC.
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