How to cut the last field from a shell string
How to cut the last field in this shell string
LINE="/string/to/cut.txt"
So that the string would look like t开发者_Go百科his
LINE="/string/to/"
Thanks in advance!
For what it's worth, a cut
-based solution:
NEW_LINE="`echo "$LINE" | rev | cut -d/ -f2- | rev`/"
I think you could use the "dirname" command. It takes in input a file path, removes the filename part and returns the path. For example:
$ dirname "/string/to/cut.txt"
/string/to
This will work in modern Bourne versions such as Dash, BusyBox ash, etc., as well as descendents such as Bash, Korn shell and Z shell.
LINE="/string/to/cut.txt"
LINE=${LINE%/*}
or to keep the final slash:
LINE=${LINE%/*}/
echo "/string/to/cut.txt" | awk -F'/' '{for (i=1; i<NF; i++) printf("%s/", $i)}'
echo $LINE | grep -o '.*/'
works too.
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