Simple division [duplicate]

This question already has answers here: 开发者_StackOverflow Why returns C# Convert.ToDouble(5/100) 0.0 and not 0.05 (7 answers) Closed 9 years ago.

I must be doing something dumb:

float ans = (i/3);

So why when i = 7 is ans coming out at 2.0?

i is an int

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It's because the / operator is performing an integer division if both operands are integers. You could do this:

float ans = (i / 3.0f);

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You need to make one of the operands a float, otherwise the calculation is done with integers first (which always results in an integer), before converting the result to a float.

float ans = ((float) i) / 3;

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It's doing integer division because i is an int and 3 is an int. Try this:

float ans = ((float)i/3.0f);

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use float ans = (i / 3.0) or float ans = (i / 3f) or float ans = ((float)i / 3). / does an integer division if both sides are of type integer.

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Very simple: in C#, int / int = int.

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What you're looking for is:

float ans = ((float)i/3);

Otherwise you're taking two integers and dividing them to find the number of whole times the divisor goes in to the dividend. (As mentioned, an int/int=int regardless of the destination type. And, to the compiler, "3" is another integer (unless you specify it as 3.0f))

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I am assuming that you have this in a loop of some sort. You could specify your i variable as a float instead.

for (float i = 0; i < 10; i++)
{
   float ans = (i/3);
   // statements
}

Just another solution.