MVC 3 Ajax.ActionLink How to get the status code in the onFailure handler?

In the action called by an Ajax action link, I need to throw an HttpException based on the current c开发者_StackOverflow中文版onditions. Depending on those conditions, the HttpException has a different code.

How do I get the status code in the onFailure handler?

I had the same problem, and I figured out you do not need to throw an HttpException. Instead do:

return new HttpStatusCodeResult(401);

The onFailure handler should look like this:

function handleOnFailure(response) {
        alert(response.status);
    }

For me the only problem is now how to handle the 401 myself instead of MVC showing the logon page. In case of a 401 the alert is not shown, but with any other statuscode this works.

Simply set AjaxOptions.OnFailure property to a function like this:

<script>
function onFailure(xhr, status) {
    alert(xhr.statusText);
}
</script>

See this post: https://www.experts-exchange.com/questions/28583187/MVC-Ajax-BeginForm-how-to-handle-OnSuccess-and-OnFailure-from-Controller.html