xslt, how to 'flatten' the tag structure for unknown number of child tags

My source file looks like this:

<x>
<names&开发者_如何学编程gt;
         <name>name1</name>
         <name>name2</name>
</names>
<codes>
         <code>code1</code>
         <code>code2</code>
</codes>
<stuff> stuff </stuff>
</x>

And I'd like to transform it to get this output:

<out>
<y>
    <name>name1</name>
    <code>code1</code>
    <stuff> stuff </stuff>
</y>
<y>
    <name>name2</name>
    <code>code2</code>
    <stuff> stuff </stuff>
</y>
</out>

I don't know the number of name and code tags in source file, but I do know the numer of names equals number of codes.

Please share some tips, how to do it.

This transformation:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>

 <xsl:template match="/*">
  <out>
   <xsl:apply-templates select="names/name"/>
  </out>
 </xsl:template>

 <xsl:template match="name">
  <xsl:variable name="vPos" select="position()"/>
  <y>
   <xsl:copy-of select="."/>
   <xsl:copy-of select=
     "../../codes/code[position()=$vPos]"/>
   <xsl:copy-of select="/*/stuff"/>
  </y>
 </xsl:template>
</xsl:stylesheet>

when applied on the provided XML document:

<x>
    <names>
        <name>name1</name>
        <name>name2</name>
    </names>
    <codes>
        <code>code1</code>
        <code>code2</code>
    </codes>
    <stuff> stuff </stuff>
</x>

produces the wanted, correct result:

<out>
   <y>
      <name>name1</name>
      <code>code1</code>
      <stuff> stuff </stuff>
   </y>
   <y>
      <name>name2</name>
      <code>code2</code>
      <stuff> stuff </stuff>
   </y>
</out>