Returning a reference to a local/temprorary object without causing a memory leak? [duplicate]

This question already has answers here: Can a local variable's memory be accessed outside its scope? (20 answers) Closed 6 years ago.

I realize this is wrong (my compiler says so!):

Rectangle& Rectangle::Overlap(const Rectangle& rectangle) {

    Point topLeft(__max(this->GetVerticies()[0]->GetX(), rectangle.GetVerticies()[0]->GetX()) - __min(this->GetVerticies()[0]->GetX() + this->GetWidth(), rectangle.GetVerticies()[0]->GetX() + rectangle.GetWidth()), 
                 (__max(this->GetVerticies()[0]->GetY(), rectangle.GetVerticies()[0]->GetY()) - __min(this->GetVerticies()[0]->GetY() + this->GetHeight(), rectangle.GetVerticies()[0]->GetY() + rectangle.GetHeight())));

    Poin开发者_开发知识库t bottomRight(__min(this->GetVerticies()[0]->GetX() + this->GetWidth(), rectangle.GetVerticies()[0]->GetX() + rectangle.GetWidth()), topLeft.GetY() + __max(this->GetVerticies()[0]->GetY() + this->GetHeight(), rectangle.GetVerticies()[0]->GetY() + rectangle.GetHeight()));

    return Rectangle(topLeft, bottomRight);
}

What would be the correct way to return the calculated rectangle without causing a memory leak? Defining the rectangle as Rectangle* result = new Rectangle(topLeft, bottomRight) then returning the dereferenced pointer works but just seems...wrong. Any suggestions?

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Either return by value:

Rectangle Rectangle::Overlap(const Rectangle& rectangle);

which does not require to change your function body, or add an additional parameter to return the result:

void Rectangle::Overlap(const Rectangle& rectangle, Rectangle& out);

and assign the result to the out parameter.

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Just change the return type to Rectangle (sans the reference).

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Just return a Rectangle instead of a reference to one.

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Make the return type a non-reference (value). Then the returned value will be fine, using the implicit copy-constructor...