Ruby on Rails - Add condition on ':include =>' to load limited number of objects

I have two models User and Event. The cardinality is one User has many Events. When I query the database to give me all the users and 开发者_如何学Ctheir corresponding events it returns the right results. Example statement: Users.find(:all, :include=>[:events])

However, what I need help with is to get events for a user based on a condition. I need for each User returned to get only Events that are scheduled for today (ex: CREATED_DATE = TODAY). That is, I don't want all events associated to Users. Said that, I still need all Users found in the database, but for some of those users that don't have an Event scheduled for today, they should not have an Event loaded in the hash map.

Can someone please help me with modifying "Users.find(:all, :include=>[:events])" Rails statement so I can get only certain Events for Users, not all Events?

Thanks, S

Something along these lines should work:

# Rails 3
User.includes(:events).where(:events => {:created_at => Time.now.midnight..Time.now.tomorrow.midnight})

# Rails 2
User.find(:all, :includes => :events, :conditions => ["events.created_at between ? and ?", Time.now.midnight, Time.now.tomorrow.midnight])

Time.now.tomorrow.midnight is pretty nasty. 1.day.from_now.midnight may be slightly less nasty, depending on your preference ;)

To my knowledge, you can't use the :include option in the way you describe.

What is your problem with getting all the events anyway? You will have to load/join/query the events table anyway. You will need more memory, though, if you instanciate all events.

Of course you could do two queries, one for the users with the events "today", and one for those without.

You could also go the other way round:

Event.find(:all, :conditions => "...only today...", :include => :user)

Which would give you all events for today with users included. You can use another query to get all users without including the events, and do the rest in memory.