How to check if timepicker1 time is oldest than timepicker2 time?
i have to select a interval of time.
i have two timepickers on my app, i need to check if timepicker1 selected time is less than timepicker2 selected time. If not, i have to show a toast to told the user the error.
I also need to do this with two datepickers,not with times in that case, but with dates.
please can someone开发者_JS百科 give me some code examples for do this?
You just need to compare the individual components of the date or time in the correct order. For time:
if (time1.getCurrentHour() < time2.getCurrentHour() || (time1.getCurrentHour() == time2.getCurrentHour() && time1.getCurrentMinute() < time1.getCurrentMinute())) {
//time 1 is earlier.
}
You might need to add in a bit of complexity depending on if you are showing 24 hour time or not.
For dates, its the same, just compare first the year then the month then the day.
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