How is -13 % 64 = -13 in PHP?

Derived from this question : (Java) How does java do modulus calculations with negative numbers开发者_运维技巧?

Anywhere to force PHP to return positive 51?

update

Looking for a configuration setting to fix, instead hard-guessing

Or other math function like bcmath?

updated

Not entire convinced by that java answer, as it does not take account of negative modulus -13+(-64) =?

Anyway, the post you referenced already gave the correct answer:

$r = $x % $n;
if ($r < 0)
{
    $r += abs($n);
}

Where $x = -13 and $n = 64.

If GMP is available, you can use gmp_mod

Calculates n modulo d. The result is always non-negative, the sign of d is ignored.

Example:

echo gmp_strval(gmp_mod('-13', '64')); // 51

Note that n and d have to be GMP number resources or numeric strings. Anything else won't work¹

echo gmp_strval(gmp_mod(-13, 64));
echo gmp_mod(-13, 64);

will both return -51 instead (which is a bug).

¹ ^{running the above in this codepad, will produce 51 in all three cases. It won't do that on my development machine.}

The modulo operation should find the remainder of division of a number by another. But strictly speaking in most mainstream programming languages the modulo operation malfunctions if dividend or/and divisor are negative. This includes PHP, Perl, Python, Java, C, C++, etc.

Why I say malfunction? Because according to mathematic definition, a remainder must be zero or positive.

The simple solution is to handle the case yourself:

if r < 0  then r = r + |divisor|;

|divisor| is the absolute value of divisor.

Another solution is to use a library (as @Gordon pointed). However I wouldn't use a library to handle a simple case like this.

I hate using if in this case when you can calculate it right away.

$r = ($x % $n + $n) % $n;

when $n is positive.

The PHP manual says that

The result of the modulus operator % has the same sign as the dividend — that is, the result of $a % $b will have the same sign as $a. For example

so this is not configurable. Use the options suggested in the question you linked to