Javascript object members that are prototyped as arrays become shared by all class instances
Has anyone noticed this behavior before? This really threw me off... I would have expected prototyped arrays to be private to each class instance rather than shared between all class instances.
Can someone verify that this is the correct behavior and perhaps explain this behavior in more detail?
Notice the commented code and how it affects the behavior of the script.
<html>
<head>
<script type="text/javascript">
function print_r( title, object ) {
var output = '';
for( var key in object ) {
output += key + ": " + object[ key ] + "\n";
}
output = title + "\n\n" + output;
alert( output );
}
function Sandwich() {
// Uncomment this to fix the problem
//this.ingredients = [];
}
Sandwich.prototype = {
"ingredients" : [],
"addIngredients" : function( ingArray ) {
for( var key in ingArray ) {
this.addIngredient( ingArray[ key ] );
}
},
"addIngredient" : function( thing ) {
this.ingredients.push( thing );
}
}
var cheeseburger = new Sandwich();
cheeseburger.addIngredients( [ "burger", "cheese" ] );
var blt = new Sandwich();
blt.addIngredients( [ "bacon", "lettuce", "tomato" ] );
var spicy_chicken_sandwich = new Sand开发者_运维知识库wich();
spicy_chicken_sandwich.addIngredients( [ "spicy chicken pattie", "lettuce", "tomato", "honey dijon mayo", "love" ] );
var onLoad = function() {
print_r( "Cheeseburger contains:", cheeseburger.ingredients );
};
</script>
</head>
<body onload="onLoad();">
</body>
</html>
Many thanks.
The prototype of an object is just an object. The prototype properties are shared between all objects that inherit from that object. No copies of the properties are made if you create a new instance of a "class" (classes don't exist anyway in JS), i.e. an object which inherits from the prototype.
It only makes a difference on how you use the these inherited properties:
function Foo() {}
Foo.prototype = {
array: [],
func: function() {}
}
a = new Foo();
b = new Foo();
a.array.push('bar');
console.log(b.array); // prints ["bar"]
b.func.bar = 'baz';
console.log(a.func.bar); // prints baz
In all these cases you are always working with the same object.
But if you assign a value to a property of the object, the property will be set/created on the object itself, not its prototype, and hence is not shared:
console.log(a.hasOwnProperty('array')); // prints false
console.log(a.array); // prints ["bar"]
a.array = ['foo'];
console.log(a.hasOwnProperty('array')); // prints true
console.log(a.array); // prints ["foo"]
console.log(b.array); // prints ["bar"]
If you want to create own arrays for each instance, you have to define it in the constructor:
function Foo() {
this.array = [];
}
because here, this refers to the new object that is generated when you call new Foo().
The rule of thumb is: Instance-specific data should be assigned to the instance inside the constructor, shared data (like methods) should be assigned to the prototype.
You might want to read Details of the object model which describes differences between class-based vs. prototype-based languages and how objects actually work.
Update:
You can access the prototype of an object via Object.getPrototypeOf(obj) (might not work in very old browsers), and Object.getPrototypeOf(a) === Object.getPrototypeOf(b) gives you true. It is the same object, also known as Foo.prototype.
The behaviour is correct.
[] is tranlated to new Array() in runtime, but only one such array is ever created.
In other words, Obj.prototype = {...} is executed just like any other assigment.
When you do var exp1 = new C(), JavaScript sets exp1.[[Prototype]] = C.prototype. When you then access properties of the instance, JavaScript first checks whether they exist on that object directly, and if not, it looks in [[Prototype]]. This means that all the stuff you define in prototype is effectively shared by all instances, and you can even later change parts of prototype and have the changes appear in all existing instances.
加载中,请稍侯......
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