invalid use of flexible array -flexible struct array as a member of another struct
I'm beginning to learn about the use of structs in C. It's challenging and enjoyable. Needless to say I've encountered a problem I can't seem to figure out. I'm trying to make a flexible st开发者_如何学JAVAruct array as a member of another struct but I'm getting an error:
invalid use of flexible array
What am I doing wrong?
#define NUM_CHANNELS 4
struct channelStruct {
float volume;
uint mute;
};
struct enginestruct
{
float bpm;
int synctimeinbeats;
int synctimeinsamples;
int currentbeat;
int oneBeatInSamples;
int samplerate;
struct channelStruct channels[];
};
struct enginestruct engine, *engineptr;
struct channelStruct channel, *channelptr;
-(void) setupengine
{
engineptr = &engine;
engineptr->oneBeatInSamples = 22050;
engineptr->samplerate = 44100;
struct channelStruct *ch = (struct channelStruct *) malloc (
NUM_CHANNELS*sizeof(struct channelStruct) );
//error occurs here
engineptr->channels = ch;
}
EDIT 1
It's something like this I am trying to achieve
flexible length struct array inside another struct using C
EDIT 2*
O.K so I seem to be approaching the creation of a variable sized array of struct the wrong way. I have 2 things that I'm trying. The first I know works for sure. The second I would just like if somebody could sanity check it for me. I'm still learning about pointers and would like to know if A is the same as B. B would be my preferred method but I don't know if its correct. I'm confident about a because when I debug channels i see channel[0],channel[1]channel[2] etc. But I'm not so confident about B because when I debug it I only see an address to memory and the variables of channel struct listed.
A
// pretty sure this is o.k to do but I would prefer
// not to have to set the size at compile time.
struct enginestruct
{
float bpm;
int synctimeinbeats;
int synctimeinsamples;
int currentbeat;
int oneBeatInSamples;
int samplerate;
channel channels[NUM_CHANNELS]; //is this technically a pointer?
};
B
//I'm not sure if this is valid. Could somebody confirm for me if
//it is allocating the same amount of space as in A.
struct enginestruct
{
float bpm;
int synctimeinbeats;
int synctimeinsamples;
int currentbeat;
int oneBeatInSamples;
int samplerate;
channel *channels;
};
//This only works if channel in the engine struct is defined as a pointer.
channel * ar = malloc(sizeof(*ar) * NUM_CHANNELS);
engineptr->channels = ar;
**EDIT 3****
Yep they are the same. Not sure when you would use one over the other tho
channel channels[NUM_CHANNELS];
Is Equal To :)
struct enginestruct
{
float bpm;
int synctimeinbeats;
int synctimeinsamples;
int currentbeat;
int oneBeatInSamples;
int samplerate;
channel *channels;
};
channel * ar = malloc(sizeof(*ar) * NUM_CHANNELS);
engineptr->channels = ar;
Edit
I think I remember now what the problem is. When you declare a struct with a flexible array as it's last member it's doing something completely different than what you think.
struct channelStruct channels[];
is NOT a pointer, it is an in place array which is contiguous with the struct.
The way this is intended to be used is to lay the struct over an existing block memory. For instance, this is useful in networking when you have a packet with variable length data. So you might do something like:
struct mydata {
// various other data fields
int varDataSize;
char data[];
}
When you receive a packet you cast a pointer to the data to a mydata
pointer and then the varDataSize
field tells you how much you've got. Like I said, the thing to remember is that it's all one contiguous block of memory and data
is NOT a pointer.
Old Answer:
I think that's only allow in the C99 standard. Try compiling with the -std=c99
flag.
Also, see this thread, Variable array in struct
Also see this SO post: Flexible array members in C - bad?
I am not an expert in this C feature but my common sense tells me that you cannot define objects of the type struct enginestruct
, only pointers. This regards the engine
variable in the following line:
struct enginestruct engine,*engineptr;
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