checking if condition for 0 value

in if condition i want to check

if(isset($_GET['q']))
{
 echo "ok";
}
esle
{
 echo "not ok";
}

when $_GET['q']=0 if send me in else part.

But i want t开发者_如何学编程o go in if .

if $_GET['q'] have any value even for 0 if should print ok

any help pls ?

This is what isset does. Try:

$x["q"] = 0;
var_dump(isset($x["q"]));

You will get true. If you think isset() returns false on 0 you are looking at the wrong place, look for a bug elsewhere.

0 is not null http://php.net/manual/en/function.isset.php

You might need something like this considering the value you want is integer

if(isset($_GET['q']) && intval($_GET['q']) > 0 )
{
 echo "ok";
}
else
{
 echo "not ok";
}

perhaps array_key_exists() would be more appropriate.

if ( array_key_exists( 'q', $_GET ) ) ...

I think this is the correct one...

if(array_key_exists('q', $_GET)){
   echo "ok";
}
else{
    echo "not ok";
}