MySQL integer unsigned arithmetic problems?
Does MySQL (5.0.45) like to do strange internal typecasts with unsigned maths? I am storing integers unsigned but when selecting basic arithmetic I ge开发者_StackOverflow社区t outrageous numbers:
mysql> create table tt ( a integer unsigned , b integer unsigned , c float );
Query OK, 0 rows affected (0.41 sec)
mysql> insert into tt values (215731,216774,1.58085);
Query OK, 1 row affected (0.00 sec)
mysql> select a,b,c from tt;
+--------+--------+---------+
| a | b | c |
+--------+--------+---------+
| 215731 | 216774 | 1.58085 |
+--------+--------+---------+
1 row in set (0.02 sec)
mysql> select (a-b)/c from tt;
+---------------------+
| (a-b)/c |
+---------------------+
| 1.1668876878652e+19 |
+---------------------+
1 row in set (0.00 sec)
mysql> -- WHAT?
mysql> select a-b from tt;
+----------------------+
| a-b |
+----------------------+
| 18446744073709550573 |
+----------------------+
1 row in set (0.02 sec)
I assume this has to do with the fact that the subtraction is negative and thus it is trying to map the results into an unsigned and overflowing? I can solve this apparently by changing everything to signed, but I'd prefer to have a little more positive space with my 32-bit integers.
I have not run into this before on MySQL and I'm pretty certain I've done lots with unsigned MySQL arithmetic; is this a common problem?
If either the left-hand side or the right-hand side of the subtraction operator is unsigned, the result is unsigned as well. You can change this by setting the NO_UNSIGNED_SUBTRACTION
SQL mode.
Alternatively, you can also explicitly cast your unsigned values to be signed bigint values and then do the subtraction.
try this:
mysql> select cast(cast(a-b as unsigned) as signed)/c from tt;
+-----------------------------------------+
| cast(cast(a-b as unsigned) as signed)/c |
+-----------------------------------------+
| -659.771639688953 |
+-----------------------------------------+
1 row in set (0.00 sec)
reference: http://dev.mysql.com/doc/refman/5.0/en/cast-functions.html
Yep, the intermediate subtraction did a 64-bit wraparound. Since you expected 32 bit integers, but actually get 64, there's no reason to use unsigned.
精彩评论