MySQL struggling with query in one to many relationship matching multiple conditions
I have two tables which are set out roughly as follows:
products product_attributes
================== ========================================
| id | name | | id | product_id | attribute | value |
================== ============================开发者_JS百科============
| 1 | product 1 | | 1 | 1 | size | big |
| 2 | product 2 | | 2 | 1 | colour | red |
| 3 | product 3 | | 3 | 2 | size | medium |
| 3 | product 3 | | 4 | 2 | age_range | 3-5 |
| .. | ... | | 5 | 2 | colour | blue |
================== | 6 | 3 | size | small |
| .. | ... | ... | ... |
========================================
There are potentially an infinite amount of attributes for a product which is why they are kept in a separate table.
I want to be able to pull out distinct products which match MULTIPLE (also infinite) attribute conditions but I cant think how to do it without maybe using an OR condition and then some sort of count to check all of the attributes were matched. Im fairly sure this isnt the best way so hopefully someone can help?!
For example find products which have size = 'medium' and colour = 'blue' (this would match product 2 in the example above).
This is a relational division problem.
The way you suggest with the COUNT
is probably the easiest in MySQL
SELECT product_id
FROM product_attributes pa
WHERE (attribute='size' and value='medium')
OR (attribute='colour' and value='blue')
GROUP BY product_id
HAVING COUNT(DISTINCT CONCAT(attribute,value) ) = 2
There is another approach with double NOT EXISTS
in the linked article but as MySQL does not support CTEs that would be quite cumbersome.
I think this should do the trick:
SELECT a.product_id, p.name FROM product_attributes AS a LEFT JOIN products p ON (a.product_id=p.id) WHERE (a.attribute="size" AND a.value="medium") OR (a.attribute="colour" AND a.value="blue") GROUP BY a.product_id
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