How to loop through PHP object with dynamic keys [duplicate]

This question already has an answer here: How to extract and access data from JSON with PHP? (1 answer) 开发者_Go百科 Closed 8 months ago.

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I tried to parse a JSON file using PHP. But I am stuck now.

This is the content of my JSON file:

{
    "John": {
        "status":"Wait"
    },
    "Jennifer": {
        "status":"Active"
    },
    "James": {
        "status":"Active",
        "age":56,
        "count":10,
        "progress":0.0029857,
        "bad":0
    }
}

And this is what I have tried so far:

<?php

$string = file_get_contents("/home/michael/test.json");
$json_a = json_decode($string, true);

echo $json_a['John'][status];
echo $json_a['Jennifer'][status];

But because I don't know the names (like 'John', 'Jennifer') and all available keys and values (like 'age', 'count') beforehand, I think I need to create some foreach loop.

I would appreciate an example for this.

---

To iterate over a multidimensional array, you can use RecursiveArrayIterator

$jsonIterator = new RecursiveIteratorIterator(
    new RecursiveArrayIterator(json_decode($json, TRUE)),
    RecursiveIteratorIterator::SELF_FIRST);

foreach ($jsonIterator as $key => $val) {
    if(is_array($val)) {
        echo "$key:\n";
    } else {
        echo "$key => $val\n";
    }
}

Output:

John:
status => Wait
Jennifer:
status => Active
James:
status => Active
age => 56
count => 10
progress => 0.0029857
bad => 0

run on codepad

---

I can't believe so many people are posting answers without reading the JSON properly.

If you foreach iterate $json_a alone, you have an object of objects. Even if you pass in true as the second parameter, you have a two-dimensional array. If you're looping through the first dimension you can't just echo the second dimension like that. So this is wrong:

foreach ($json_a as $k => $v) {
   echo $k, ' : ', $v;
}

To echo the statuses of each person, try this:

<?php

$string = file_get_contents("/home/michael/test.json");
if ($string === false) {
    // deal with error...
}

$json_a = json_decode($string, true);
if ($json_a === null) {
    // deal with error...
}

foreach ($json_a as $person_name => $person_a) {
    echo $person_a['status'];
}

?>

---

The most elegant solution:

$shipments = json_decode(file_get_contents("shipments.js"), true);
print_r($shipments);

Remember that the json-file has to be encoded in UTF-8 without BOM. If the file has BOM, then json_decode will return NULL.

Alternatively:

$shipments = json_encode(json_decode(file_get_contents("shipments.js"), true));
echo $shipments;

---

Try

<?php
$string = file_get_contents("/home/michael/test.json");
$json_a = json_decode($string,true);

foreach ($json_a as $key => $value){
  echo  $key . ':' . $value;
}
?>

---

It's completely beyond me that no one pointed out that your begining "tags" are wrong. You're creating an object with {}, while you could create an array with [].

[ // <-- Note that I changed this
    {
        "name" : "john", // And moved the name here.
        "status":"Wait"
    },
    {
        "name" : "Jennifer",
        "status":"Active"
    },
    {
        "name" : "James",
        "status":"Active",
        "age":56,
        "count":10,
        "progress":0.0029857,
        "bad":0
    }
] // <-- And this.

With this change, the json will be parsed as an array instead of an object. And with that array, you can do whatever you want, like loops etc.

---

Try This

    $json_data = '{
    "John": {
        "status":"Wait"
    },
    "Jennifer": {
        "status":"Active"
    },
    "James": {
        "status":"Active",
        "age":56,
        "count":10,
        "progress":0.0029857,
        "bad":0
      }
     }';

    $decode_data = json_decode($json_data);
    foreach($decode_data as $key=>$value){

            print_r($value);
    }

---

Try:

$string = file_get_contents("/home/michael/test.json");
$json = json_decode($string, true);

foreach ($json as $key => $value) {
    if (!is_array($value)) {
        echo $key . '=>' . $value . '<br />';
    } else {
        foreach ($value as $key => $val) {
            echo $key . '=>' . $val . '<br />';
        }
    }
}

---

More standard answer:

$jsondata = file_get_contents(PATH_TO_JSON_FILE."/jsonfile.json");

$array = json_decode($jsondata,true);

foreach($array as $k=>$val):
    echo '<b>Name: '.$k.'</b></br>';
    $keys = array_keys($val);
    foreach($keys as $key):
        echo '&nbsp;'.ucfirst($key).' = '.$val[$key].'</br>';
    endforeach;
endforeach;

And the output is:

Name: John
 Status = Wait
Name: Jennifer
 Status = Active
Name: James
 Status = Active
 Age = 56
 Count = 10
 Progress = 0.0029857
 Bad = 0

---

Loop through the JSON with a foreach loop as key-value pairs. Do type-checking to determine if more looping needs to be done.

foreach($json_a as $key => $value) {
    echo $key;
    if (gettype($value) == "object") {
        foreach ($value as $key => $value) {
          # and so on
        }
    }
}

---

<?php
$json = '{
    "response": {
        "data": [{"identifier": "Be Soft Drinker, Inc.", "entityName": "BusinessPartner"}],
        "status": 0,
        "totalRows": 83,
        "startRow": 0,
        "endRow": 82
    }
}';
$json = json_decode($json, true);
//echo '<pre>'; print_r($json); exit;
echo $json['response']['data'][0]['identifier'];
$json['response']['data'][0]['entityName']
echo $json['response']['status']; 
echo $json['response']['totalRows']; 
echo $json['response']['startRow']; 
echo $json['response']['endRow']; 

?>

---

Try it:

foreach ($json_a as $key => $value)
 {
   echo $key, ' : ';
   foreach($value as $v)
   {
       echo $v."  ";
   }
}

---

When you decode a json string, you will get an object. not an array. So the best way to see the structure you are getting, is to make a var_dump of the decode. (this var_dump can help you understand the structure, mainly in complex cases).

<?php
     $json = file_get_contents('/home/michael/test.json');
     $json_a = json_decode($json);
     var_dump($json_a); // just to see the structure. It will help you for future cases
     echo "\n";
     foreach($json_a as $row){
         echo $row->status;
         echo "\n";
     }
?>

---

$json_a = json_decode($string, TRUE);
$json_o = json_decode($string);



foreach($json_a as $person => $value)
{
    foreach($value as $key => $personal)
    {
        echo $person. " with ".$key . " is ".$personal;
        echo "<br>";
    }

}

---

The quickest way to echo all json values is using loop in loop, the first loop is going to get all the objects and the second one the values...

foreach($data as $object) {

        foreach($object as $value) {

            echo $value;

        }

    }

---

You have to give like this:

echo  $json_a['John']['status']; 

echo "<>"

echo  $json_a['Jennifer']['status'];

br inside <>

Which gives the result :

wait
active

---

I am using below code for converting json to array in PHP, If JSON is valid then json_decode() works well, and will return an array, But in case of malformed JSON It will return NULL,

<?php
function jsonDecode1($json){
    $arr = json_decode($json, true);
    return $arr;
}

// In case of malformed JSON, it will return NULL
var_dump( jsonDecode1($json) );
?>

If in case of malformed JSON, you are expecting only array, then you can use this function,

<?php
function jsonDecode2($json){
    $arr = (array) json_decode($json, true);
    return $arr;
}

// In case of malformed JSON, it will return an empty array()
var_dump( jsonDecode2($json) );
?>

If in case of malformed JSON, you want to stop code execution, then you can use this function,

<?php
function jsonDecode3($json){
    $arr = (array) json_decode($json, true);

    if(empty(json_last_error())){
        return $arr;
    }
    else{
        throw new ErrorException( json_last_error_msg() );
    }
}

// In case of malformed JSON, Fatal error will be generated
var_dump( jsonDecode3($json) );
?>