How would I parse in a bash script date_value _space_ date_value

I am trying to import a tsv file into a mysql db but I am having trouble since the file has no unique delimiters to identify where a new row starts. The only unique identifier is a date followed by a space followed by time. Example: 6/19/2010 16:04:43

Could someone please point me in the right direction or help me make a bash script that puts a semicolon ";" in front of that string. So the end result will be ;6/19/2010 16:04:43

The tricky part is that in this file there will be other date fields and other t开发者_运维百科ime fields but this is the only string that will have a space in between the two.

cat file | sed 's#[0-9]\{1,2\}/[0-9]\{1,2\}/[0-9]\{4\} #;&#g' >resultfile. Test before using.