How to serve stylesheet in Django

i want to use css in Django templates..If i give CSS with in the templates it gets working. But i want to use in static serve manner.

settings.py

       DEBUG =True
       MEDIA_ROOT = 'C:/WorkBase/Python/first/static/'
       MEDIA_URL = '/static/'
       ADMIN_MEDIA_PREFIX = '/media/'

TEMPLATE_DIRS = (

      'C:/WorkBase/Python/first/templates',
       )

TEMPLATE_LOADERS = (

      'django.template开发者_StackOverflow中文版.loaders.filesystem.load_template_source',
      'django.template.loaders.app_directories.load_template_source',
      'django.template.loaders.eggs.load_template_source',

)

urls.py

        from django.conf import settings

        if settings.DEBUG:
                urlpatterns +=patterns(' ',
                (r'^static/(?p<path>.*)$','django.views.static.serve',{'document_root':settings.MEDIA_ROOT}),

)

I got 'unexpected end of pattern' error for above line

         <link rel="stylesheet" type="text/css" href="/static/css/style.css"/>

I believe the 'P' to name the pattern needs to be capitalized. r'^static/(?P<path>.*)$'

All of the examples and doc show it capitalized. Python Regex Doc

T. Stone has hit the nail on the head with his answer. Here's what I use, for an example:

if settings.DEBUG:
        urlpatterns += patterns('',
                (r'^static/(?P<path>.*)$', 'django.views.static.serve',
                        { 'document_root': os.path.join(os.path.dirname(__file__), "static")}),
        )