How to get the max timestamp and groupby another field in LINQ to Entities
I have an Entity with the following fields GUID TaskId, GUID SubTaskId, DateTime Timestamp
The TaskId may be one-to-many with the SubTaskId. It's like a composite key almost.
I would like to write an expression or expressions resulting in the newest among each TaskId i.e.
TaskId SubTaskId 开发者_StackOverflow中文版 Timestamp
1 A 2010-11-22 15:48:49.727 1 B 2010-11-22 16:24:51.117 2 C 2010-11-15 11:49:05.717 2 D 2010-11-15 14:02:11.467Would result in a sequence containing only:
TaskId SubTaskId Timestamp 1 B 2010-11-22 16:24:51.117 2 D 2010-11-15 14:02:11.467This expression works just fine for showing all TaskId's and TimeStamps
var q1 =
from req in myEntity
orderby req.TaskId
select new
{
req.TaskId,
req.SubTaskId,
req.Timestamp
};
but I would like to show only the latest Timestamp for each TaskId. All my attempts at adding a max to the expression fail. The posting (http://stackoverflow.com/questions/2034800/how-do-you-find-the-group-wise-max-in-linq) seemed close, but I couldn't translate it into something working. Perhaps a foreach
is needed.
How about this?
var q1 =
from req in myEntity
group req by req.TaskId into g
let topReq = g.OrderByDescending(r => r.Timestamp).FirstOrDefault()
select new
{
topReq.TaskId,
topReq.SubTaskId,
topReq.Timestamp
};
var tasks = new[] {
new { TaskId = 1, SubTaskId = "A", Timestamp = DateTime.Parse("2010-11-22 15:48:49.727")},
new { TaskId = 1, SubTaskId = "B", Timestamp = DateTime.Parse("2010-11-22 16:24:51.117")},
new { TaskId = 2, SubTaskId = "C", Timestamp = DateTime.Parse("2010-11-15 11:49:05.717")},
new { TaskId = 2, SubTaskId = "D", Timestamp = DateTime.Parse("2010-11-15 14:02:11.467")}};
var newestTasks =
from task in tasks
group task by task.TaskId into g
select g.Where(t => t.Timestamp == g.Max(t2 => t2.Timestamp)).Single();
foreach (var task in newestTasks)
Console.WriteLine("TaskId = {0}, SubTaskId = {1}, Timestamp = {2}",
task.TaskId, task.SubTaskId, task.Timestamp);
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