cannot pass a subclass pointer to a function when the function need a reference to the parent pointer, why?

class Parent{

};

class Child:
   public Parent
{

}

void Func(Parent*& param)
{

}

Ch开发者_StackOverflow中文版ild* c=new Child;

Func(c); //error

Here's the reason why:

struct Parent {};

struct Child: Parent { int a; };

void Func(Parent*& param) { param = new Parent(); }

int main() {
    Child* c = 0;

    Func(c); // suppose this was allowed, and passed a reference to "c".
    c->a;    // oh dear. The purpose of a type system is to prevent this.
}

If you can change Func to take Parent *const &, that would be OK.

See the C++ FAQ item "21.2 Converting Derived* → Base* works OK; why doesn't Derived** → Base** work?".

Note that this is the same problem as converting Derived*& to Base*&.

Cheers & hth.,

This is by design.

c is not a Parent*, it is a Child*. To turn it into a Parent*, an implicit conversion is required. This implicit conversion generates a temporary Parent* object (at least conceptually), and a non-const reference cannot be bound to a temporary object.