How to print last two columns using awk

All I want is the last two columns printed.开发者_如何转开发

You can make use of variable NF which is set to the total number of fields in the input record:

awk '{print $(NF-1),"\t",$NF}' file

this assumes that you have at least 2 fields.

awk '{print $NF-1, $NF}'  inputfile

Note: this works only if at least two columns exist. On records with one column you will get a spurious "-1 column1"

@jim mcnamara: try using parentheses for around NF, i. e. $(NF-1) and $(NF) instead of $NF-1 and $NF (works on Mac OS X 10.6.8 for FreeBSD awkand gawk).

echo '
1 2
2 3
one
one two three
' | gawk '{if (NF >= 2) print $(NF-1), $(NF);}'

# output:
# 1 2
# 2 3
# two three

using gawk exhibits the problem:

 gawk '{ print $NF-1, $NF}' filename
1 2
2 3
-1 one
-1 three
# cat filename
1 2
2 3
one
one two three

I just put gawk on Solaris 10 M4000: So, gawk is the cuplrit on the $NF-1 vs. $(NF-1) issue. Next question what does POSIX say? per:

http://www.opengroup.org/onlinepubs/009695399/utilities/awk.html

There is no direction one way or the other. Not good. gawk implies subtraction, other awks imply field number or subtraction. hmm.

Please try this out to take into account all possible scenarios:

awk '{print $(NF-1)"\t"$NF}'  file

or

awk 'BEGIN{OFS="\t"}' file

or

awk '{print $(NF-1), $NF} {print $(NF-1), $NF}' file

try with this

$ cat /tmp/topfs.txt
/dev/sda2      xfs        32G   10G   22G  32% /

awk print last column
$ cat /tmp/topfs.txt | awk '{print $NF}'

awk print before last column
$ cat /tmp/topfs.txt | awk '{print $(NF-1)}'
32%

awk - print last two columns
$ cat /tmp/topfs.txt | awk '{print $(NF-1), $NF}'
32% /