开发者

C Programming - File - fwrite

I've got a question regarding programming and files.

while(current!=NULL)
{
  if(current->Id_Doctor!='\0')
  {
    current=current->next;
    id_doc=(current->Id_Doctor);
  }
  if(current->Id_Doctor=='\0')
  {
    id_doc=id_doc+1;
    printf("%d", id_doc);
    break;
  }
}
fwrite(&id_doc, sizeof(char), 1, Archivo);

I dont know why but it aint writing the value of id_doc on the binary file called 'Archivo'...what could be the problem? I added a printf of id_doc and the value was printed..I really dont know

Ok, heres the full code(more-less):

struct Medico
{
  int Id_Doctor;
  int Estado;
  char Nombre[60];
  char Clave_Acceso[20];
  char Especialidad[40]; 
  struct Medico *next;
};
void Dar_Alta_Med (int estado);
void MenuPrincipal(char enta);
int main(void)
{
  char enta;
  MenuPrincipal(enta);
}
void Dar_Alta_Med(int estado)
{
  struct Medico * head = NULL;
  struct Medico * prev, *current;
  char nombre_doc[60], especialida[40], password[20];
  int id_doc=0, estado_doc=1;
  FILE *Archivo;
 const char *md1="\n<md>\n";
  const char *id_doc1="<id_doctor> ";
 Archivo=fopen("md.dat", "ab+");
  fwrite(md1, 1, strlen(md1), Archivo);
  fwrite(id_doc1, 1, strlen(id_doc1), Archivo);
  current = (struct Medico *) malloc (sizeof(struct Medico));
  current->Id_Doctor=id_doc; 
  while(current!=NULL)
    {
      if(current->Id_Doctor!='\0')
    {
开发者_运维知识库      current=current->next;
      id_doc=(current->Id_Doctor);
    }
      else
    {
      id_doc=id_doc+1;
      printf("%d", id_doc);
      break;
    }
    }
  fwrite(&id_doc, sizeof(id_doc), 1, Archivo);
  printf("Ingresa el nombre del Doctor a dar de alta: ");
  fclose(Archivo);
}

Im dying here, please help :/


Try adding fflush(Archivo); to force a write of all buffered data.

Also, this statement: if(current->Id_Doctor=='\0') really ought to be an else since there is no other thing it can be but '\0'


Three things:

  • Make sure your fopen is successful.

    Archivo=fopen("md.dat", "ab+");
    if (Archivo == NULL)
    {
         perror("Failed to open file Archivo");
         ...
    }
    
  • Make sure you are checking the success of your fwrite's.

    if (fwrite(&id_doc, sizeof(id_doc), 1, Archivo) < 1)    
    {    
         perror("Failed to write to file Archivo");
         ... 
    }
    
  • Make sure you have a fclose to close the file properly.

    if (fclose(Archivo) != 0)    
    {    
        perror("Failed to close file Archivo");     
        ...
    }
    

Now that you've post a full sample of your code I guess I should ask if error checking is just left out for brevity? If not, you should think about adding it.

If you're expecting the value of id_doc to be in display format in the output file you'll have to convert the int to a string (using snprintf or similar) and write the string to the output file instead.


fwrite(&id_doc, sizeof(char), 1, Archivo); 

If you defined id_doc as anything other than a char it will write \0 to the file.

Much cleaner would be:

fwrite(&id_doc, sizeof(id_doc), 1, Archivo); 


If your first current is an Id_Doctor you have an endless loop.

If there is no current after your last current that is not an Id_Doctor, you get an illegal pointer derefenciation.

For your Problem: try the flush() family.


You're passing a pointer to a FOUR-BYTE INT, but only writing ONE BYTE (the wrong byte)!

Solution: declare id_doc as "char", not "int".


You have previously written the strings "\n<md>\n" and"<id_doctor> " to the file Archivo, which seems to indicate that it is not a binary file at all, but rather an XML-style file.

In this case, what you almost certainly want is:

fprintf(Archivo, "%d", id_doc);
0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜