sitecore: get absolute url in a xslt rendering
I开发者_JS百科 want to pass the absolute url of the current page to sharing services of facebook/twitter/linkedin. How do I get the absolute url of a page from a xslt rendering
I can at least tell you how this is done in a .NET sublayout, not sure if that helps:
Sitecore.Links.UrlOptions urlOptions = new Sitecore.Links.UrlOptions();
urlOptions.AlwaysIncludeServerUrl = true;
string url = Sitecore.Links.LinkManager.GetItemUrl(Sitecore.Context.Item, urlOptions);
Set other options on urlOptions as appropriate.
Happy coding.
I realize this is an old question, but the answer given really isn't the full picture. You can build an XSLT extension to handle this:
public class XslExtensions : Sc.Xml.Xsl.XslHelper
{
public string GetUrl(XPathNodeIterator iterator)
{
Sc.Data.Items.Item item = this.GetRequiredItem(iterator);
return item.GetUrl(); // Extension method for Item that returns the URL as a string
}
public Sc.Data.Items.Item GetRequiredItem(XPathNodeIterator iterator)
{
Sc.Diagnostics.Assert.IsNotNull(iterator, "iterator");
if (!iterator.MoveNext())
{
XsltException ex = new XsltException("No iterator.");
Sc.Diagnostics.Log.Error(ex.Message, ex, this);
throw ex;
}
Sc.Data.Items.Item item = this.GetItem(iterator);
if (item == null)
{
XsltException ex = new XsltException("No item.");
Sc.Diagnostics.Log.Error(ex.Message, ex, this);
throw ex;
}
return item;
}
}
Then you need to add the class that holds the above to the <xslExtensions>
node:
<extension mode="on" type="MyProject.XslExtensions, MyProject" namespace="http://myproject.com/extensions" singleInstance="true" />
And finally you can use the method. First reference the extensions...
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:sc="http://www.sitecore.net/sc"
xmlns:sql="http://www.sitecore.net/sql"
xmlns:myp="http://myproject.com/extensions"
exclude-result-prefixes="sc sql myp">
Then use!
<xsl:value-of select="myp:GetUrl(.)" />
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