MYSQL Query most recent entry
Here is the problem. I need to transform this query to get the right information and Im not sure how.
Database info
Id | Client_Code | Time_Date | Employee_Name | Date_Time | Time_Stamp
1 | 000010 | 2010-11-17 07:45:00| Jerry | 2010-11-17| 07:45 AM
2 | 000022 | 2010-11-17 07:30:00| Jerry | 2010-11-17| 07:30 AM
3 | 000010 | 2010-11-17 16:00:00| Bill | 2010-11-17| 04:00 PM
4 | 000022 | 2010-11-17 16:00:00| Bill | 2010-11-17| 04:00 PM
Here is the query
$sql = "SELECT Client_Code, MAX(TIME(Time_Date)), Employee_Name, Date_Time, Time_Stamp FROM Transaction WHERE Date_Time = CURdate()
AND Time_Stamp != '' GROUP BY Client_Code";
Here is what i get with this query and phpcode
echo " $row[Employee_Name], $row[Client_Code], ".$row['MAX(TIME(Time_Date))']."<br>";
Jerry, 000010, 16:00:00
Bill, 000022, 16:00:00
For some reason yes its giving me the right 16:00:00 Time but it is not giving me the right employee name with that time. It has something to do with the grouping I think but the group has to be by client_code first because I want the most recent entry for each Client_Code. Also I can not use ID for grouping because inputs are not always in order. Here is what is should look like.
Bill, 000010, 16:00:00
Bill, 000022, 16:00:00
Can anyone tell me how to fix this query to get the correct information please. Also on开发者_开发问答ce the mysql query is corrected Ill need it to count each employee up and display the results like so.
Bill, 2
Use a self join:
SELECT x.client_code,
TIME(x.time_date)
x.employee_name,
x.date_time,
x.time_stamp
FROM TRANSACTION x
JOIN (SELECT t.client_code,
MAX(t.time_date) AS max_time_date
FROM TRANSACTION t
WHERE t.date_time = CURRENT_DATE
AND t.time_stamp != ''
GROUP BY t.client_code) y ON y.client_code = x.client_code
AND y.max_time_date = x.time_date
WHERE x.date_time = CURRENT_DATE
AND x.time_stamp != ''
You have to add "order by id desc limit 0,1" to your query or you can try to mysql_last_insert_id
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