What am I missing in the following program?
#include<stdio.h> 开发者_Go百科
#define TOTAL_ELEMENTS (sizeof(array) / sizeof(array[0]))
int array[] = {23, 34, 12, 17, 204, 99, 16};
int main() {
int d;
for (d = -1; d <= (TOTAL_ELEMENTS - 2); d++)
printf("%d\n", array[d + 1]);
return 0;
}
Why is the for loop not run even once?
The issue is that sizeof()
returns size_t
which is unsigned. Comparison of -1
with TOTAL_ELEMENTS - 2
should result in a warning indicating you have compared unsigned with signed. When this comparison happens, the -1
is converted to an unsigned value which is MAX_UINT
. On a 32-bit platform, both -1
and MAX_UINT
are 0xFFFFFFFF
.
Your TOTAL_ELEMENTS()
macro could incorporate a cast to (int)
but that isn't technically correct because size_t
has a larger value range than int
. Best to change your loop variable so that it is declare as size_t
and never becomes negative.
You're mixing signed and unsigned arithmetic. sizeof yields a size_t (an unsigned type). When you do the d <= (TOTAL_ELEMENTS -2)
the d
gets converted to unsigned, and then compared. Since -1
becomes the largest value in the target type when converted to unsigned, your condition becomes something like 0xffffffff <= 5
, which is always false so the loop never executes.
Because TOTAL_ELEMENTS
is an unsigned value (type size_t
) and d
is a signed value (type int
, which is most likely signed on your platform, and you're certainly assuming it is even if it isn't). The compiler in this case is converting d
to an unsigned value, and converting -1 to an unsigned value usually results in SIZE_MAX
or something similar, which is certainly greater than TOTAL_ELEMENTS - 2
. To do this correctly, cast the unsigned value to a signed value: (int)(TOTAL_ELEMENTS - 2)
.
Out of curiosity, why are you starting your index at -1 and then adding 1 to it in the loop? Why not just do this:
unsigned i;
for(i = 0; i < (TOTAL_ELEMENTS); i++)
printf("%d\n", array[i]);
It would be much clearer than what you have.
You could
#define TOTAL_ELEMENTS ((int)(sizeof(array) / sizeof(array[0])))
assuming array
will always be small enough. After all, you are using an integer to walk through the elements of the array.
I'm not sure. Does sizeof do what you think it does here? It's been a while but I think you might be computing the size of an int*
when you call sizeof (array)
, which would be 1 (1 byte). Dividing that by the size of an int, which is usually 4 bytes, would certainly mean your loop never runs.
edit: it seems more likely that d is being converted to an unsigned type. The other posters may be correct.
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