I have a MySQL database that contains many tables, some of them created dynamically by the software. The dynamic tables have a consistent naming scheme:

dynamic_1  
dynamic_2  
...

However, I don't necessarily know how many of these tables there are.

I'd like to be able to delete all of these dynamic tables without dropping the entire database. I'd like 开发者_JS百科to be able to do this purely in SQL. (Stored procedures are ok.) Is this is even possible?

Quick addendum.

The solution from Haim and Alexandre works great, but there's one special case we all missed. What if there are -no- dynamic tables? In that case @v will be NULL and we get an error when we try to execute. I added a second variable to handle this case:

SET @v = (SELECT CONCAT('drop table ', GROUP_CONCAT(a.table_name)) FROM information_schema.tables a where a.table_schema = DATABASE() AND a.table_name like 'dynamic_%');
SET @y = (SELECT IF (@V IS NOT NULL, @V, 'select 1'));
PREPARE s FROM @y;
EXECUTE s; 

you can run this query and get all the sql queries that you need to run;

select concat( 'drop table ', a.table_name, ';' )
from information_schema.tables a 
where a.table_name like 'dynamic_%';

you can insert it to file like

INTO OUTFILE '/tmp/delete.sql';

update according to alexandre comment

SET @v = ( select concat( 'drop table ', group_concat(a.table_name))
    from information_schema.tables a 
    where a.table_name like 'dynamic_%'
    AND a.table_schema = DATABASE()
;);
 PREPARE s FROM @v; 
EXECUTE s;