convert double to int

What is the best way to convert a开发者_JAVA技巧 double to an int? Should a cast be used?

You can use a cast if you want the default truncate-towards-zero behaviour. Alternatively, you might want to use Math.Ceiling, Math.Round, Math.Floor etc - although you'll still need a cast afterwards.

Don't forget that the range of int is much smaller than the range of double. A cast from double to int won't throw an exception if the value is outside the range of int in an unchecked context, whereas a call to Convert.ToInt32(double) will. The result of the cast (in an unchecked context) is explicitly undefined if the value is outside the range.

if you use cast, that is, (int)SomeDouble you will truncate the fractional part. That is, if SomeDouble were 4.9999 the result would be 4, not 5. Converting to int doesn't round the number. If you want rounding use Math.Round

Yeah, why not?

double someDouble = 12323.2;
int someInt = (int)someDouble;

Using the Convert class works well too.

int someOtherInt = Convert.ToInt32(someDouble);

The best way is to simply use Convert.ToInt32. It is fast and also rounds correctly.

Why make it more complicated?

Convert.ToInt32 is the best way to convert

My ways are :

 - Convert.ToInt32(double_value)
 - (int)double_value
 - Int32.Parse(double_value.ToString());

None of the code samples exhibit the normal behaviour a school kid would expect (that halves are rounded up). What most people would expect is is this:

double d = 1.5;
int i = (int)Math.Round(d, MidpointRounding.AwayFromZero);

Here is a complete example

class Example 
{    
  public static void Main() 
  {    
    double x, y; 
    int i; 

    x = 10.0; 
    y = 3.0; 

    // cast double to int, fractional component lost (Line to be replaced) 
    i = (int) (x / y); 
    Console.WriteLine("Integer outcome of x / y: " + i); 
  }    
}

If you want to round the number to the closer integer do the following:

i = (int) Math.Round(x / y); // Line replaced

There is no better. It really depends on what you want, performance, accuracy, etc.

But see differences https://dotnetfiddle.net/kwqF2M

double testeDouble_min = 12.3456;
double testeDouble_max = 12.8456;
double emptyDouble;

int i01_min = Convert.ToInt32(testeDouble_min); //12
int i01_max = Convert.ToInt32(testeDouble_max); //13
//var erro = Convert.ToInt32(emptyDouble); //error  

int i02_min = (int)testeDouble_min; //12
int i02_max = (int)testeDouble_max; //12
//var erro = (int)emptyDouble; //error  

var styles = System.Globalization.NumberStyles.Integer | System.Globalization.NumberStyles.AllowDecimalPoint;
var provider = new System.Globalization.CultureInfo("en-US");
bool success = int.TryParse(testeDouble_min.ToString(), styles, provider, out int i03_min); //0

_ = int.TryParse(testeDouble_max.ToString(),  out int i03_max); //0 because it has decimal place, if it didn't have ok

int i04_min = (int)Math.Round(testeDouble_min, MidpointRounding.AwayFromZero); //12
int i04_max = (int)Math.Round(testeDouble_max, MidpointRounding.AwayFromZero); //13

About IL there are no big differences between (int) or Convert.ToInt32

var dd = 12.3;
int a = (int)dd;

result:

    IL_0000: nop
    IL_0001: ldc.r8 12.3
    IL_000a: stloc.0
    IL_000b: ldloc.0
    IL_000c: conv.i4
    IL_000d: stloc.1
    IL_000e: ret

(int) in theory less instructions tend to be faster, but I doubt anyone can measure that.

And

var dd = 12.3;
int b = Convert.ToInt32(dd);

result:

    IL_0000: nop
    IL_0001: ldc.r8 12.3
    IL_000a: stloc.0
    IL_000b: ldloc.0
    IL_000c: call int32 [System.Private.CoreLib]System.Convert::ToInt32(float64)
    IL_0011: stloc.1
    IL_0012: ret

int myInt = (int)Math.Ceiling(myDouble);

I think the best way is Convert.ToInt32.

label8.Text = "" + years.ToString("00") + " years";

when you want to send it to a label, or something, and you don't want any fractional component, this is the best way

label8.Text = "" + years.ToString("00.00") + " years";

if you want with only 2, and it's always like that