SqlServer Rand() question
I am writing a procedure where each call it needs to get a single random number. This procedure is called from our .net web service.
I tried implementing this using rand(). However, when I have multiple calls to the stored procedure within milliseconds, I am getting a lot of collisions in that the same random number is being generated. If there is a space of about 20 or 30 ms between subsequent calls it appears to work ok.
It appears that rand() is reseeded each stored procedure call by SqlServer. From what I understand this is a problem because one should seed a random number generator once and that one doesn't get a good sequence of pseudo-random numbers if one is reseeding each call to rand. Also, it appears that calls to the same sp that are within 1 or 2 milliseconds get seeded with the same value.
Here is the statement itself in the stored procedure.
DECLARE @randomNumber char(9)
SET @randomNumber = RIGHT('00000' + CAST(CAST(rand()*100000 AS INT) AS VARCHAR(5)),5)
+ RIGHT('00000' + CAST(CAST(rand()*10000 AS INT) AS VARCHAR(4)),4)
Does anyone have a suggestion for fixing this?
Will I have to write my own random number generator that is seeded once and saves its state in a table across calls? How does SQL Server seed rand()? Is it truly rando开发者_运维知识库m or if you call an sp within 1 or 2 milliseconds of each other on separate connections will it be seeded with the same seed causing a collision?
If you are using SQL Server 2008, then you can use the CRYPT_GEN_RANDOM() function. This will randomize data for every row even if you were trying to calculate millions of random numbers in one query execution and doesn't have any seeding issues:
SELECT CAST(RIGHT(CAST(CAST(CRYPT_GEN_RANDOM(1) AS INT) AS VARCHAR(100)), 1) AS INT)
Here's the link to the BOL article:
http://msdn.microsoft.com/en-us/library/cc627408.aspx
In your example, replace rand()*10000
with ABS(CHECKSUM(NEWID())) % 9999
However, for char(9):
SELECT RIGHT('000000000' + CAST(ABS(CHECKSUM(NEWID()) % 999999999) AS char(9), 9)
To seed RAND randomly...
RAND(CHECKSUM(NEWID()))
Edit:
Note, RAND is badly implemented in SQL Server. Don't use it.
You could use a table with just an identifier field for creating unique nunbers to use as seed:
declare
@randomNumber char(9),
@seed1 int,
@seed2 int
insert into SeedTable () values ()
set @seed1 = scope_identity()
insert into SeedTable () values ()
set @seed2 = scope_identity()
set @randomNumber = right('00000' +
cast(cast(rand(@seed1) * 100000 as int) as varchar(5)), 5) +
right('00000' +
cast(cast(rand(@seed2) * 10000 as int) as varchar(4)), 4)
if (@seed2 > 10000) truncate table SeedTable
The RAND() function has an optional seed parameter that you could use for this. If you pass the last generated random value as a seed to the next call to rand(), you are guaranteed to get a new random number.
Thanks to gbn for pointing out that the seed is an integer, while rand() returns a float. With that knowledge, here's a working example! First create a table:
create table RandomNumber (number float)
insert into RandomNumber values (rand())
Then grab a random number and store the new number in a transaction:
declare @new float
begin transaction
select @new = rand(-2147483648 + 4294967295 * number)
from RandomNumber with (updlock, holdlock)
update RandomNumber set number = @new
commit transaction
print 'Next bingo number is: ' + cast(cast(@new*100 as int) as varchar)
An SQL Server integer varies between -2147483648 and 2147483647, and a random number is a float between 0.0 and 1.0. So -2147483648 + 4294967295 * number
should cover the full range of available integers.
The transaction ensures that only one connection at a time reads and stores a new number. So the numbers are random even on different connections to SQL Server. (By the way, I voted for gbn's answer, seems much easier.)
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