how to find number of mondays or tuesdays between two dates?

I have start date and end date.

I need to find out the day that is Sunday 开发者_如何学JAVAor Monday etc dependent upon user click on check box.

How can I find/calculate that in PHP?

The answer by w35I3y was almost correct, but I was getting errors using that function. This function correctly calculates the number of Mondays or any specific day between two given dates:

/** 
* Counts the number occurrences of a certain day of the week between a start and end date
* The $start and $end variables must be in UTC format or you will get the wrong number 
* of days  when crossing daylight savings time
* @param - $day - the day of the week such as "Monday", "Tuesday"...
* @param - $start - a UTC timestamp representing the start date
* @param - $end - a UTC timestamp representing the end date
* @return Number of occurences of $day between $start and $end
*/
function countDays($day, $start, $end)
{        
    //get the day of the week for start and end dates (0-6)
    $w = array(date('w', $start), date('w', $end));

    //get partial week day count
    if ($w[0] < $w[1])
    {            
        $partialWeekCount = ($day >= $w[0] && $day <= $w[1]);
    }else if ($w[0] == $w[1])
    {
        $partialWeekCount = $w[0] == $day;
    }else
    {
        $partialWeekCount = ($day >= $w[0] || $day <= $w[1]);
    }

    //first count the number of complete weeks, then add 1 if $day falls in a partial week.
    return floor( ( $end-$start )/60/60/24/7) + $partialWeekCount;
}

Example Usage:

$start = strtotime("tuesday UTC");    
$end = strtotime("3 tuesday UTC");       
echo date("m/d/Y", $start). " - ".date("m/d/Y", $end). " has ". countDays(0, $start, $end). " Sundays";

Outputs something like: 09/28/2010 - 10/19/2010 has 3 Sundays.

You could create a function that uses strtotime() recursively to count the number of days. Since strtotime("next monday"); works just fine.

function daycount($day, $startdate, $counter)
{
    if($startdate >= time())
    {
        return $counter;
    }
    else
    {
        return daycount($day, strtotime("next ".$day, $startdate), ++$counter);
    }
}

echo daycount("monday", strtotime("01.01.2009"), 0);

Hopefully this is something you're looking for :)

This question is just crying out for an updated answer that uses PHP's DateTime classes, so here it is:-

/**
 * @param String $dayName eg 'Mon', 'Tue' etc
 * @param DateTimeInterface $start
 * @param DateTimeInterface $end
 * @return int
 */
function countDaysByName($dayName, \DateTimeInterface $start, \DateTimeInterface $end)
{
    $count = 0;
    $interval = new \DateInterval('P1D');
    $period = new \DatePeriod($start, $interval, $end);

    foreach($period as $day){
        if($day->format('D') === ucfirst(substr($dayName, 0, 3))){
            $count ++;
        }
    }
    return $count;
}

no loops and no recursivity

<?php
define('ONE_WEEK', 604800); // 7 * 24 * 60 * 60

function number_of_days($days, $start, $end) {
    $w = array(date('w', $start), date('w', $end));
    $x = floor(($end-$start)/ONE_WEEK);
    $sum = 0;

    for ($day = 0;$day < 7;++$day) {
        if ($days & pow(2, $day)) {
            $sum += $x + ($w[0] > $w[1]?$w[0] <= $day || $day <= $w[1] : $w[0] <= $day && $day <= $w[1]);
        }
    }

    return $sum;
}

//$start = $end = time();

// 0x10 == pow(2, 4) == 1 << 4 // THURSDAY
// 0x20 == pow(2, 5) == 1 << 5 // FRIDAY
echo number_of_days(0x01, $start, $end); // SUNDAY
echo number_of_days(pow(2, 0), $start, $end); // SUNDAY
echo number_of_days(0x02, $start, $end); // MONDAY
echo number_of_days(pow(2, 1), $start, $end); // MONDAY
echo number_of_days(0x04, $start, $end); // TUESDAY
echo number_of_days(1 << 2, $start, $end); // TUESDAY
echo number_of_days(0x08, $start, $end); // WEDNESDAY
echo number_of_days(1 << 3, $start, $end); // WEDNESDAY
echo number_of_days(0x10, $start, $end); // THURSDAY
echo number_of_days(0x20, $start, $end); // FRIDAY
echo number_of_days(0x40, $start, $end); // SATURDAY
echo number_of_days(0x01 | 0x40, $start, $end); // WEEKENDS : SUNDAY | SATURDAY
echo number_of_days(0x3E, $start, $end); // WORKDAYS : MONDAY | TUESDAY | WEDNESDAY | THURSDAY | FRIDAY
?>

To count The Total Friday Between Two Dates##

$from_date=(2015-01-01);

$to_date=(2015-01-20);

while(strtotime($from_date) <= strtotime($to_date)){

    //5 for count Friday, 6 for Saturday , 7 for Sunday

    if(date("N",strtotime($from_date))==5){
        $counter++;
    }
    $from_date = date ("Y-m-d", strtotime("+1 day", strtotime($from_date)));

}

echo $counter;

<?php
$date = strtotime('2009-01-01');
$dateMax = strtotime('2009-02-23');

$nbr = 0;
while ($date < $dateMax) {
  var_dump(date('Y-m-d', $date));
  $nbr++;
  $date += 7 * 24 * 3600;
}
echo "<pre>";
 var_dump($nbr);
?>

function daycount($day, $startdate, $enddate, $counter) {
    if($startdate >= $enddate) {
        return $counter-1;  // A hack to make this function return the correct number of days.
    } else {
        return $this->daycount($day, strtotime("next ".$day, $startdate), $enddate, ++$counter);
    }
}

This is a different version of the first answer which takes a start and end point and works for me. All of the examples given on this page seemed to return the answer plus an additional day for some reason.

w35l3y's answer seems to work well, so I up-voted it. Still, I preferred something a bit easier to follow, and with less math and looping (not sure it matters from a performance standpoint, though). I think I covered all the possible scenarios... Here's what I came up with:

function numDays($sday, $eday, $i, $cnt) {
    if (($sday < $eday && $i >= $sday && $i <= $eday) || ($sday > $eday && ($i >= $sday || $i <= $eday))) {
        // partial week (implied by $sday != $eday), so $i (day iteration) may have occurred one more time
        // a) end day is ahead of start day; $i is within start/end of week range
        // b) start day is ahead of end day (i.e., Tue start, Sun end); $i is either in back half of first week or front half of second week
        $cnt++;
    } elseif ($sday == $eday && $i == $sday) {
        // start day and end day are the same, and $i is that day, i.e., Tue occurs twice from Tue-Tue (1 wk, so $wks = $cnt)
        $cnt++;
    }

    return $cnt;    // # of complete weeks + partial week, if applicable
}

Notes: $sday and $eday are the day numbers corresponding to the start and end of the range to be checked, and $i is the day number being counted (I have it in a 0-6 loop). I moved $wks outside the function, as there's no point recalculating it each time.

$wks = floor(($endstamp - $startstamp)/7*24*60*60);
$numDays = numDays($sday, $eday, $i, $wks);

Make sure the start/end timestamps you're comparing have the same timezone adjustment, if any, otherwise you'll always be off a bit with $cnt and $wks. (I ran into that when counting from an unadjusted first of the year to an adjusted day/time X.)

Correct day count. This will count all the Days from Monday to Sunday between 2 given date

 <?php

    $startdate='2018-04-01';
    $enddate='2018-04-20';

    $mondayCount = 0;
    $tuesday = 0;
    $wednesday = 0;
    $thursday = 0;

    $friday = 0;
    $saturday = 0;
    $sunday = 0;

    $begin = new DateTime($startdate );
    $end = new DateTime( $enddate );
    $end = $end->modify( '+1 day' );

    $interval = new DateInterval('P1D');
    $daterange = new DatePeriod($begin, $interval ,$end);
    // looping each days from FROM and TO dates

    foreach($daterange as $date) {
        //$eachDate = $date->format("d-m-Y");
        echo $eachDateName = $date->format("l");
        switch ($eachDateName)
        {
            case 'Monday' :
                $mondayCount++;break;
            case 'Tuesday' :
                $tuesday++;break;
            case 'Wednesday' :
                $wednesday++;break;
            case 'Thursday' :
                $thursday++;break;
            case 'Friday' :
                $friday++;break;
            case 'Saturday' :
                $saturday++;break;
            case 'Sunday' :
                $sunday++;break;
        }

    }
    echo $mondayCount;echo "---";
    echo $tuesday;echo "---";
    echo $wednesday;echo "---";
    echo $thursday;echo "---";
    echo $friday;echo "----";
    echo $saturday;echo "---";
    echo $sunday;
?>

Hope this will help someone

I got the answer.Its working for sunday only.But I dont know how to make it for another days

<?php

// Define a constant of 1 day in seconds
define(ONE_DAY, 86400); 
date_default_timezone_set('America/New_York'); 

// Accepts two timestamps, start and end 
// Returns an array of timestamps that fall on a sunday 
function sundays_in_range($start, $end) {    
    echo date('N', $start);
    echo "<br/>";                     
    $days_until_sunday = date('w', $start) > 0 ? 7 - date('w', $start) : 0; 

    $date = $start + (ONE_DAY * $days_until_sunday); 
    $sundays = array(); 
    while ($date <= $end) { 
        array_push($sundays, $date); 
        $date += (7 * ONE_DAY); 
    } 
    return $sundays; 
} 

// Calculate some example dates. Today, and 30 days from now 
$start = time($start); 
$end = time($end) + (30 * ONE_DAY); 
echo ONE_DAY;
echo "<br/>";
 $count=0;
// Loop and output Y-m-d 
foreach (sundays_in_range($start, $end) as $sunday)
{
print "<option>".date("Y-m-d", $sunday)."</option><br/>";
 $count++;
 }

echo  $count;
?>