How to wait for async to finish

I would like to run some async workflow, then wait for it to finish before printing some results, example:

let dowork n =
    async {
        do printfn "work %d" n
    }

let creatework() =
    async {
        for x in [1..5] do
            Async.Start(dowork x)
    }

Async.RunSynchronously(creatework())    
printfn "finished"

when I run this, I want all the dowork calls to finish before printing "finished". However I get results like this:

work 2 work 3 work 4 work 5 finished work 1

I have tried removing async from creatework() but "finished" is printed before the async wo开发者_Go百科rkflows are run.

In the real dowork, the program performs some IO, so I want to wait for the slowest one to finish before continuing.

Well answering my own question seems lame, but this seems to work. Someone come up with something better so I can award them the answer :)

let dowork n =
    async {
        do printfn "work %d" n
    }

let creatework() =
    [1..5] |> Seq.map dowork |> Async.Parallel |> Async.RunSynchronously

creatework()    
printfn "finished"

It gives various output, but "finished" so far is always last...

I found that it's convenient to use MailboxProcessor to make sure that all side-effects (e.g. printfn) happen on the same thread. Use MailboxProcessor.PostAndReply(singleResult) to funnel work results (be it just the strings to print) into the same synchronization context, and provide for another message type that returns aggregate values. One could use a union for types of these messages.