Can You Use Arithmetic Operators to Flip Between 0 and 1

Is there a way without usin开发者_运维问答g logic and bitwise operators, just arithmetic operators, to flip between integers with the value 0 and 1?

ie. variable ?= variable will make the variable 1 if it 0 or 0 if it is 1.

x = 1 - x

Will switch between 0 and 1.

Edit: I misread the question, thought the OP could use any operator

A Few more...(ignore these)

x ^= 1       // bitwise operator
x = !x       // logical operator
x = (x <= 0) // kinda the same as x != 1

Without using an operator?

int arr[] = {1,0}
x = arr[x]

Yet another way:

x = (x + 1) % 2

Assuming that it is initialized as a 0 or 1:

x = 1 - x

Comedy variation on st0le's second method

x = "\1"[x]

Another way to flip a bit.

x = ABS(x - 1) // the absolute of (x - 1)

int flip(int i){
    return 1 - i;
};

Just for a bit of variety:

x = 1 / (x + 1);

x = (x == 0);

x = (x != 1);

Not sure whether you consider == and != to be arithmetic operators. Probably not, and obviously although they work in C, more strongly typed languages wouldn't convert the result to integer.

you can simply try this

+(!0) // output:1

+(!1) // output:0

You can use simple: abs(x-1) or just: int(not x)