Suppress JavaScript undefined errors?

I have written a script that checks a set of radiobuttons to be checked. But due to different possibilities different radiobuttons will show. Is there a way to suppress JavaScript errors when it pops undefined/getElementById is null? Something like the @-char does in PHP?

Update:

A bit more background info. I've made a website where users can submit images and another party for whom the images are can select their top 3 of the images. So each image has three radiobuttons. The difficulty here lies in the fact that the radiobuttons must be controlled dimensional (horizontal and vertical), because a submitted image may only be at place 1, 2 or 3. This is my working code. But adding many if(!var == undefined) doesn't make the code prettier. Therefor I'm wondering if there is something like @suppressMe is possible?

function HandleRadioButtons(id, type, idString, img)
{
    var idArray = idString.split("|");  
    var place1  = document.getElementById("G_" + id);
    var place2  = document.getElementById("S_" + id);
    var place3  = document.getElementById("B_" + id);
    var img1    = document.getElementById("Winner1");
    var img2    = document.getElementById("Winner2");
    var img3    = document.getElementById("Winner3");    

    switch(type)
    {
        case "G" :
            place2.checked = false;
            place2.disabled = true;
            place3.checked = false;
            place3.disabled = true;
            img1.style.background = 'url(' + img + ') no-repeat center center #FFF';
            break;
        case "S" :
            place1.checked = false;
            place1.disabled = true;
            place3.checked = false;
            place3.disabled = true;
            img2.style.background = 'url(' + img + ') no-repeat center center #FFF';
            break;
        case "B" :
            place1.checked = false;
            place1.disabled = true;
            place2.checked = false;
            place2.disabled = true;
            im开发者_如何学Cg3.style.background = 'url(' + img + ') no-repeat center center #FFF';
            break;
    }     

    var current1, current2, current3 = "";

    for(i = 0; i < idArray.length - 1; i++)
    {
        var place1 = document.getElementById("G_" + idArray[i]);
        var place2 = document.getElementById("S_" + idArray[i]);
        var place3 = document.getElementById("B_" + idArray[i]);

        if(place1.checked == true)
        {
            var current1 = idArray[i];            
        }

        if(place2.checked == true)
        {
            var current2 = idArray[i];            
        }

        if(place3.checked == true)
        {
            var current3 = idArray[i];            
        }
    }

    for(i = 0; i < idArray.length - 1; i++)
    {        
        var place1 = document.getElementById("G_" + idArray[i]);
        var place2 = document.getElementById("S_" + idArray[i]);
        var place3 = document.getElementById("B_" + idArray[i]);

        if(idArray[i] != id && idArray[i] != current1 && idArray[i] != current2 && idArray[i] != current3)
        {
            switch(type)
            {
                case "G" :
                    place1.disabled = false;
                    place2.disabled = false;
                    place3.disabled = false;
                    break;
                case "S" :
                    place1.disabled = false;
                    place2.disabled = false;
                    place3.disabled = false;
                    break;
                case "B" :
                    place1.disabled = false;
                    place2.disabled = false;
                    place3.disabled = false;
                    break;
            }
        }
    }   
}

You can easily test for a null or undefined value in JavaScript, as both these values are falsy:

var element = document.getElementById('some-id');
if (element) {
   element.value = 'Hello';
}

You could also consider using a try/catch block:

try {
   var element = document.getElementById('some-id');
   element.value = 'Hello';

   // ... the rest of your code here.
}
catch (e) {
   if (!(e instanceof TypeError)) {
      // The exception is not a TypeError, so throw it again.
      throw e;
   }
}

However be careful that the above will suppress all the TypeError exceptions and that might make your code more difficult to debug.

you can check if buttons are existing by getElementById and then check its length. Are you using any framework?

Try this

var element = document.getElementById('some-id');
element?.value = 'Hello';