Finding Max Number in an Array C Programming
I am trying to find the max number in an array. I have created a function and I am using the following code:
int maxValue( int myArray [], int size)
{
int i, maxValue;
maxValue=myArray[0];
//find the largest no
for (i=0;i)
{
if (myArray[i]>maxValue)
maxValue=myArray[i];
}
return maxValue;
}
However I get a syntax error before )
token. What am I doing wrong a开发者_如何学Pythonnd am I even doing this right? Any help would be greatly appreciated.
You must pass a valid array with at least one member to this function:
#include<assert.h>
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
int
maxValue(int myArray[], size_t size) {
/* enforce the contract */
assert(myArray && size);
size_t i;
int maxValue = myArray[0];
for (i = 1; i < size; ++i) {
if ( myArray[i] > maxValue ) {
maxValue = myArray[i];
}
}
return maxValue;
}
int
main(void) {
int i;
int x[] = {1, 2, 3, 4, 5};
int *y = malloc(10 * sizeof(*y));
srand(time(NULL));
for (i = 0; i < 10; ++i) {
y[i] = rand();
}
printf("Max of x is %d\n", maxValue(x, sizeof(x)/sizeof(x[0])));
printf("Max of y is %d\n", maxValue(y, 10));
return 0;
}
By definition, the size of an array cannot be negative. The appropriate variable for array sizes in C is size_t
, use it.
Your for
loop can start with the second element of the array, because you have already initialized maxValue
with the first element.
A for loop has three parts:
for (initializer; should-continue; next-step)
A for loop is equivalent to:
initializer;
while (should-continue)
{
/* body of the for */
next-step;
}
So the correct code is:
for (i = 0; i < size; ++i)
the paren after the for seems to be missing some contents.
normally it should be something like
for (i=0; i<size; i++)
include:
void main()
{
int a[50], size, v, bigv;
printf("\nEnter %d elements in to the array: ");
for (v=0; v<10; v++)
scanf("%d", &a[v]);
bigv = a[0];
for (v=1; v<10; v++)
{
if(bigv < a[v])
bigv = a[v];
}
printf("\nBiggest: %d", bigv);
getch();
}
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