MySQL's DATE_ADD function in PHP
I need to implement the MySQL DATE_ADD functionality in PHP, so I have taken the function provided on the official PHP website at the "strtotime" documentation page like follows:
function get_x_months_to_the_future( $base_time = null, $months = 1 )
{
if (is_null($base_time))
$base_time = time();
$x_months_to_the_future = strtotime( "+" . $months . " months", $base_time );
$month_before = (int) date( "m", $base_time ) + 12 * (int) date( "Y", $base_time );
$mon开发者_Go百科th_after = (int) date( "m", $x_months_to_the_future ) + 12 * (int) date( "Y", $x_months_to_the_future );
if ($month_after > $months + $month_before)
$x_months_to_the_future = strtotime( date("Ym01His", $x_months_to_the_future) . " -1 day" );
return $x_months_to_the_future;
} //get_x_months_to_the_future()
It works perfectly, but I don't understand why in the $month_before and $month_after calculation the year is multiplied by 12 in both cases. What difference does that make and is that really needed? I simply don't know why and would like to understand that code completely.
I think I just realized why... because it converts the years to months and then adds the other months... d'oh! :-)
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