Parsing JSON object in PHP using json_decode

I tried to request the weather from a web service supplying data in JSON format. My PHP request code, which did not succeed was:

$url="http://www.worldweatheronline.com/feed/weather.ashx?q=schruns,austria&format=json&num_of_days=5&key=8f2d1ea151085304102710";
$json = file_get_contents($url);
$data = json_decode($json, TRUE);
echo $data[0]->weather->weatherIconUrl[0]->value;    

This is some of the data that was returned. Some of the details have been truncated for brevity, but object integrity is retained:

{ "data": 
    { "current_condition": 
        [ { "cloudcover": "31",
            ... } ],  
      "request": 
        [ { "query": "Schruns, Austria",
            "type": "City" } ],
      "weather": 
        [ { "date": "2010-10-27",
            "precipMM": "0.0",
            "tempMaxC": "3",
            "tempMaxF": "38",
            "tempMinC": "-13",
            "tempMinF": "9",
            "weatherCode": "113",
            "weatherDesc": [ {"value": "Sunny" } ],
            "weatherIconUrl": [ {"value": "http:\/\/www.worldweatheronline.com\/images\/wsymbols01_png_64\/wsymbol_0001_sunny.png" } ],
            "winddir16Point": "N",
            "winddirDegree": "356",
            "winddirection": "N",
            "windspeedKmph": "5",
 开发者_运维技巧           "windspeedMiles": "3" }, 
          { "date": "2010-10-28",
            ... },

          ... ]
        }
    }
}

This appears to work:

$url = 'http://www.worldweatheronline.com/feed/weather.ashx?q=schruns,austria&format=json&num_of_days=5&key=8f2d1ea151085304102710%22';
$content = file_get_contents($url);
$json = json_decode($content, true);

foreach($json['data']['weather'] as $item) {
    print $item['date'];
    print ' - ';
    print $item['weatherDesc'][0]['value'];
    print ' - ';
    print '<img src="' . $item['weatherIconUrl'][0]['value'] . '" border="0" alt="" />';
    print '<br>';
}

If you set the second parameter of json_decode to true, you get an array, so you cant use the -> syntax. I would also suggest you install the JSONview Firefox extension, so you can view generated json documents in a nice formatted tree view similiar to how Firefox displays XML structures. This makes things a lot easier.

If you use the following instead:

$json = file_get_contents($url);
$data = json_decode($json, TRUE);

The TRUE returns an array instead of an object.

Try this example

$json = '{"foo-bar": 12345}';

$obj = json_decode($json);
print $obj->{'foo-bar'}; // 12345

http://php.net/manual/en/function.json-decode.php

NB - two negatives makes a positive . :)

Seems like you forgot the ["value"] or ->value:

echo $data[0]->weather->weatherIconUrl[0]->value;

When you json decode , force it to return an array instead of object.

$data = json_decode($json, TRUE); -> // TRUE

This will return an array and you can access the values by giving the keys.

You have to make sure first that your server allow remote connection so that the function file_get_contents($url) works fine , most server disable this feature for security reason.

While editing the code (because mild OCD), I noticed that weather is also a list. You should probably consider something like

echo $data[0]->weather[0]->weatherIconUrl[0]->value;

to make sure you are using the weatherIconUrl for the correct date instance.