ActiveRecord Association without Foreign Key
I am trying to build a relationship model between users. A user can either initiate a relation, or receive a relation from another user. Therefore, the relations table in the db has the foreign keys "initiator_id" and "recipient_id".
开发者_如何学GoNow, I can figure what relations the user initiated or received using the following associations:has_many :initiated_relations, :foreign_key => :initiator_id, :class_name => 'Relation', :dependent => :destroy
has_many :received_relations, :foreign_key => :recipient_id, :class_name => 'Relation', :dependent => :destroy
What I am trying to do, is build an association that will fetch me all relations that belong to a user (either initiated or received). Trying the following does not work, and complains about the lack of "user_id" field:
has_many :relations, :conditions => 'recipient_id = #{id} or initiator_id = #{id}'
How can I create an association that is solely based on the conditions field, without looking for the default foreign_key? Or is there perhaps a completely different approach to solving this?
From your comments to @neutrino's answer I understand, that you only need this "relation" for read only operations. If you're on Rails 3 you can utilize the fact, that it uses lazy fetching. The where()
method returns ActiveRecord::Relation
object, which you can later modify. So you can define a method like this:
def User < ActiveRecord::Base
def all_relations
Relation.where("initiator_id => ? OR recipient_id = ?", id, id)
end
end
And then you can do:
User.all_relations.where(:confirmed => true).all
Well, I can think of using finder_sql
for that:
has_many :relations, :finder_sql => 'select * from relations right outer join users
on relations.recipient_id = #{id} or relations.initiator_id = #{id}'
Apart from that, you can just write a method that will return a united array of the two relations associations', but you will lose the advantage of an association interface (phew).
Perhaps someone will come up with a better solution.
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